Answer:
a) 2.01 g
Explanation:
- Na₂CO₃ (s) + 2AgNO₃ (aq) → Ag₂CO₃ (s) + 2NaNO₃
First we <u>convert 0.0302 mol AgNO₃ to Na₂CO₃ moles</u>, in order to <em>calculate how many Na₂CO₃ moles reacted</em>:
- 0.0302 mol AgNO₃ *
= 0.0151 mol Na₂CO₃
So the remaining Na₂CO₃ moles are:
- 0.0340 - 0.0151 = 0.0189 moles Na₂CO₃
Finally we <u>convert Na₂CO₃ moles into grams</u>, using its <em>molar mass</em>:
- 0.0189 moles Na₂CO₃ * 106 g/mol = 2.003 g Na₂CO₃
The closest answer is option a).
Add a coefficient 2 before H2O and a 2 before SO2.
Element on the right side of the periodic table differ from the elements on the left side in that elements on the <em>right side are non metallic and tends to be gases at room temperature.</em>
<em> </em><u>Explanation</u>
In the periodic table there element in the right side , left side and those which are in between.
- Example of element in the right side is fluorine chlorine, neon, Argon among others.
- This element have higher effective nuclear charges and stabilize electrons more effectively.
- there electrostatic intermolecular forces are generally weak therefore they exist in liquid or gaseous state.
I think 1.00 mol sorry if I’m wrong
Im taking lambda as x (wavelength)
m = 0.17 kg
v=37m/s
h=6.62*10^-34m²kg/s
x= h/mv
