3x-6+10x+15=35
10x+3x=35-15+6
13x=26
x=2
Answer:
Pop in 1990 = 81 million rats
Pop in 2005 = 127 million rats
Step-by-step explanation:
Given the function, the population of rats in 1990 is when we replace t with "0" which strictly gives the coefficient 81 that represents 81 million rats.
The rat population in 2005 is given by the formula when t = 15
This is: approximately 127 million rats.
Using the z-distribution, it is found that a sample size of 1066 is required.
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which z is the z-score that has a p-value of .
The margin of error is:
From the previous study, the estimate is of 0.23, hence .
98% confidence level, hence, z is the value of Z that has a p-value of , so .
The sample size is <u>n for which M = 0.03</u>, hence:
Rounding up, a sample size of 1066 is required.
A similar problem is given at brainly.com/question/12517818
I believe the answer is A