Find the soluiton
2x+2y=16
3x-y=4
x+y=8
<u>3x-y=4+</u>
4x=12
x=3
3(3)-y=4
9-y=4
y=5
(3,5)
test them to see if get true statment
obviously the first equatons of 1,2,4 work
1 doesn't work
2, works
4. doesn't work
2 is the same as the first except both euations are just doubled
answer is 2
Answer: y= -2 (x+1)
Step-by-step explanation:
this would be the “inverse” of the original equation making them cross at exactly 1 point
(5,24)
- The two areas are the same.
- To find the area, we multiply the side lengths. Y=area
Rectangle 1: side lengths 4 and (x+1)
y=4(x+1)= 4x+4
Rectangle 2: side lengths 3 and (2x-2)
y=3(2x-2)= 6x-6
- Since the two areas are same, we can conclude that
4x+4=6x-6
-2x=-10, x=5
- Since x is 5, we can plug it into the equations to find y.
Option 1 with rectangle 1: y=4(5)+4, y=24
Option 2 with rectangle 2: y=6(5)-5, y=24
I graphed the linear equation on desmos.