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3 years ago

Help meeeeeeeeeeewweeee

Chemistry

1 answer:

Maurinko [17]3 years ago

6 0

<h3>Hey Mate Here Is Your Answer:-</h3>

<h3>C- Diffusion</h3>

Reason:- The Mechanism of Diffusion In the case of food coloring in water, the water is the solvent while the food coloring is the solute. Once they've mixed, they make a solution. Diffusion takes time, though how much time depends on the kinetic energy of the molecules randomly bouncing among each other.

<h3>Hope This Helps You ❤️</h3>

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2) Show the calculation of Kc for the following reaction if an initial reaction mixture of 0.800 mole of CO and 2.40 mole of H2

nadezda [96]

Answer:

Kc = 3.90

Explanation:

CO reacts with $H_2$ to form $CH_4$ and $H_2O$ . balanced reaction is:

$CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g) + H_2O(g)$

No. of moles of CO = 0.800 mol

No. of moles of $H_2$ = 2.40 mol

Volume = 8.00 L

Concentration = $\frac{Moles}{Volume\ in\ L}$

Concentration of CO = $\frac{0.800}{8.00} = 0.100\ mol/L$

Concentration of $H_2$ = $\frac{2.40}{8.00} = 0.300\ mol/L$

$CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g) + H_2O(g)$

Initial 0.100 0.300 0 0

equi. 0.100 -x 0.300 - 3x x x

It is given that,

at equilibrium $H_2O (x)$ = 0.309/8.00 = 0.0386 M

So, at equilibrium CO = 0.100 - 0.0386 = 0.0614 M

At equilibrium $H_2$ = 0.300 - 0.0386 × 3 = 0.184 M

At equilibrium $CH_4$ = 0.0386 M

$Kc=\frac{[H_2O][CH_4]}{[CO][H_2]^3}$

$Kc=\frac{0.0386 \times 0.0386}{(0.184)^3 \times 0.0614} =3.90$

8 0

4 years ago

Hey besties can y'all help me out

Lostsunrise [7]

you need to <u>lose one electron </u>

5 0

3 years ago

Help plz !!!!!!!!!!!!

melamori03 [73]

Heat given off by burning coal is Potential Energy and Laser Light is Kinetic Energy.

4 0

3 years ago

Two people are trying to push a large box across a floor. Each person pushes with an equal amount of force. The total amount of

Charra [1.4K]

Answer:

C- 250+250= 500 newtons (the amount the both exerted) :)

Explanation:

5 0

3 years ago

Read 2 more answers

What is the mass of snow (in tons) on a 150.0ft by 45.0 ft flat roof after a 6.0 inch snowfall? Assume that 11 inches of snow is

Aneli [31]

6 inches of snowfall would be equivalent to 6/11 inches of water or 6/132 feet. So the volume of the equivalent amount of water on the roof is 150 ft. x 45 ft. x 6/132ft. = 306.8 cubic feet.
Since there are 907185 grams in a ton and 28316.8 mL in a cubic foot, 1.00 g/mL is equivalent to 0.0312 tons/cubic foot
Multiplying the two results gives 9.58 tons of snow.

5 0

3 years ago