The median of the data set is 4. The interquartile range is UQ-LQ 5-3=2. The mean of the first set is 3.5. The mean of the second set is 5.5. Since every score went up by two, the mean went up by two as well.
I hope that helps.
Answer:
292.45 m
Step-by-step explanation:
Both disk are at an angle of 38.48°
From the image below we calculate as,
For disk B, direct distance is 1.296 km from receiver = 1296 m
Vertical height from ground will be = 1296 x sin38.48 = 806.42 m
For disk A, direct distance is 826 m from receiver
Verival height above ground = 826 x sin38.48 = 513.97 m
Difference in height between disks is 806.42 - 513.97 = 292.45 m
Answer:
1. Infinitiely many solutions, one solution, no solutions
2.
y=-3/2x-4
y= x+1
3.
y=1/4x-2
y=1/4x+3
Step-by-step explanation: