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inessss [21]
3 years ago
11

Give me lil reasoning so I know your not lying for points

Chemistry
1 answer:
rjkz [21]3 years ago
5 0
1mL=0.001L
so if you have 300mL, multiply that by 0.001 to give you 0.3L
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Which reaction is an oxidation-reduction reaction?
sweet [91]

Answer:

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saponification palmitate

5 0
3 years ago
Calculate the ph of a dilute solution that contains a molar ratio of potassium acetate to acetic acid (pka ???? 4.76) of (a) 2:1
givi [52]

According to Hasselbach-Henderson equation:

pH=pK_{a}+log\frac{[A^{-}]}{[HA]}

Here, [A^{-}] is concentration of conjugate base and [HA] is concentration of acid.

In the given problem, conjugate base is CH_{3}COOK and acid is CH_{3}COOH thus, Hasselbach-Henderson equation will be as follows:

pH=pK_{a}+log\frac{[CH_{3}COOK]}{[CH_{3}COOH]}...... (1)

(a) Ratio of concentration of potassium acetate and acetic acid is 2:1 thus,

\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=2

Also, pK_{a}=4.76

Putting the values in equation (1),

pH=4.76+log\frac{2}{1}=5.06

Therefore, pH of solution is 5.06.

(b) Ratio of concentration of potassium acetate and acetic acid is 1:3 thus,

\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{1}{3}

Also, pK_{a}=4.76

Putting the values in equation (1),

pH=4.76+log\frac{1}{3}=4.28

Therefore, pH of solution is 4.28.

(c)Ratio of concentration of potassium acetate and acetic acid is 5:1 thus,

\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{5}{1}

Also, pK_{a}=4.76

Putting the values in equation (1),

pH=4.76+log\frac{5}{1}=5.45

Therefore, pH of solution is 5.45.

(d) Ratio of concentration of potassium acetate and acetic acid is 1:1 thus,

\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=1

Also, pK_{a}=4.76

Putting the values in equation (1),

pH=4.76+log\frac{1}{1}=4.76

Therefore, pH of solution is 4.76.

(e) Ratio of concentration of potassium acetate and acetic acid is 1:10 thus,

\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{1}{10}

Also, pK_{a}=4.76

Putting the values in equation (1),

pH=4.76+log\frac{1}{10}=3.76

Therefore, pH of solution is 3.76.

4 0
3 years ago
Calculate the percentrage of neutral form of aspirin that is present in the stomach ph 1.
Korolek [52]

Answer:

The 99.68% of the aspirin is present in the neutral form

Explanation:

Aspirin, Acetylsalicylic acid, is a weak acid with pKa = 3.5

Using Henderson-Hasselbalch equation:

pH = pKa + log [A⁻] / [HA]

<em>Where [A⁻] is the ionized form and HA the neutral form of the acid</em>

<em />

Replacing with a pH of stomach of 1.0:

1.0 = 3.5 + log [A⁻] / [HA]

-2.5 = log [A⁻] / [HA]

3.16x10⁻³ = [A⁻] / [HA] <em>(1)</em>

<em />

A 100% of aspirin is = [A⁻] + [HA]

100 = [A⁻] + [HA] <em>(2)</em>

<em></em>

Replacing (2) in (1)

3.16x10⁻³ = 100 - [HA] / [HA]

3.16x10⁻³[HA] = 100 - [HA]

1.00316 [HA] = 100

[HA] = 99.68%

<h3>The 99.68% of the aspirin is present in the neutral form</h3>
8 0
3 years ago
How many atoms are in 3.5 moles of NaCl?
Ivenika [448]

Answer:

2.11  ×10²⁴ atoms

Explanation:

Given data:

Number of moles of NaCl = 3.5 mol

Number of atoms = ?

Solution:

It is known that 1 mole contain 6.022×10²³ atoms. The number 6.022×10²³ is called Avogadro number.

3.5 mol ×6.022×10²³ atoms / 1 mol

21.1 ×10²³ atoms

2.11  ×10²⁴ atoms

5 0
3 years ago
PLZ ANSWER
satela [25.4K]

Answer:

B. The student should model a convex lens because it directs light toward the center of the lens.

Explanation:

Lenses are optical devices that work on the principle of refraction.

Refraction is a phenomenon of wave (such as light waves) that occurs when a ray of light crosses the interface between two mediums with different optical density: when this occurs, the ray of light bends and change speed.

In particular, there are two types of lenses:

  • Convex lenses: these lenses are curved outward at their center, therefore the rays of light coming from infinite distance (parallel to the axis) are all focused into a point of the lens, called principal focus. Therefore, a convex lens directs lights towards this point.
  • Concave lenses: these lenses are curved inward at their center, therefore the rays of light coming from infinite distance are bent away from the principal focus. Therefore, this is a diverging lens, as the rays of light do not converge.

So, the correct answer is

B. The student should model a convex lens because it directs light toward the center of the lens.

7 0
3 years ago
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