<u>Answer:</u> The mass of chlorine needed by the plant per day is
<u>Explanation:</u>
We are given:
Volume o water treated per day = 25,000,000 gallons
Converting this volume from gallons to liters, we use the conversion factor:
1 gallon = 3.785 L
So,
Amount of chlorine applied for disinfection = 10 mg/L
Applying unitary method:
For 1 L of water, the amount of chlorine applied is 10 mg
So, for of water, the amount of chlorine applied will be
Hence, the mass of chlorine needed by the plant per day is
The balanced chemical reaction for the described reaction above is,
Na2CO3 + 2HCl ---> 2NaCl + H2CO3
From the reaction, 1 mole of Na2CO3 is needed to produce 2 moles of NaCl. In terms of mass, 106 grams of Na2CO3 are needed to produce 116.9 grams of NaCl. From this,
(23.4 g NaCl) x (106 g Na2CO3 / 116.9 NaCl = 21.22 g Na2CO3
Thus, approximately 21.22 g Na2CO3 is needed for the desired reaction.
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Answer: a) The of acetic acid at is
b) The percent dissociation for the solution is
Explanation:
cM 0 0
So dissociation constant will be:
Give c= 0.10 M and = ?
Also
Putting in the values we get:
b)