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3 years ago

5

what is the formula equation for the reaction between sulfuric acid and dissolved sodium hydroxide if all products and reactants

are in the aqueous or liquid phase?

1 answer:

Rama09 [41]3 years ago

4 0

This reaction would produce salt and water- Sodium Sulphate and Water.

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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Match the following aqueous solutions with the appropriate letter from the column on the right.1. 0.19 m AgNO3 2. 0.17 m CrSO4 3

vichka [17]

Answer:

0.13 m of $Mn(NO_3)_2$ → Highest boiling point

0.19 m of $AgNO_3$ → Second Highest boiling point

0.17 m of $CrSO_4$ → Third highest boiling point

0.31 m Sucrose (nonelectrolyte) → Lowest boiling point

Explanation:

Elevation in boiling is given by :

$\Delta T_b=i\times k_b\times m$

Where :

i = van't Hoff factor

$k_b$ = Molal Elevation constant of solvent

m = molaity of the solution

1) 0.19 m of $AgNO_3$

$AgNO_3\rightarrow Ag^++NO_3^{-}$

i = 2 (electrolyte)

Molality of the solution = 0.19

Elevation is boiling point of solution:

$\Delta T_b=2\times k_b\times 0.19 m$

$\Delta T_b=0.38 m\times k_b$

2) 0.17 m of $CrSO_4$

$CrSO_4\rightarrow Cr^{2+}+SO_4^{2-}$

i = 2 (electrolyte)

Molality of the solution = 0.17

Elevation is boiling point solution :

$\Delta T_b=2\times k_b\times 0.17 m$

$\Delta T_b=0.34 m\times k_b$

3) 0.13 m of $Mn(NO_3)_2$

$Mn(NO_3)_2\rightarrow Mn^{2+}+2NO_3^{-}$

i = 3 (electrolyte)

Molality of the solution = 0.13

Elevation is boiling point solution :

$\Delta T_b=3\times k_b\times 0.13 m$

$\Delta T_b=0.39 m\times k_b$

4) 0.31 m Sucrose (nonelectrolyte)

i = 1 ( non electrolyte)

Molality of the solution = 0.31 m

Elevation is boiling point solution :

$\Delta T_b=1\times k_b\times 0.31 m$

$\Delta T_b=0.31 m\times k_b$

Higher the value of elevation in temperature higher will be the boiling point of the solution .

The decreasing order of solution from highest boiling point to lowest boiling point is :

$0.39 m\times k_b>0.38 m\times k_b>0.34 m\times k_b>0.31 m\times k_b$

0.13 m of $Mn(NO_3)_2$ → Highest boiling point

0.19 m of $AgNO_3$ → Second Highest boiling point

0.17 m of $CrSO_4$ → Third highest boiling point

0.31 m Sucrose (nonelectrolyte) → Lowest boiling point

6 0

3 years ago

Add a nail in CuSO4 Sodium, the colour of CuSO4 disappears why?

Gre4nikov [31]

The iron nail displaces the Cu from the copper sulfate solution. This results in the color of CuSO4's disappearance. Copper is less reactive than iron.

5 0

3 years ago

Read 2 more answers

If 16.5g of c6h14o2 are reacted vwith .499 mol of o2. How many moles of co2 should be produced

Fed [463]

Answer:

moles of carbon dioxide produced are 410.9 mol.

Explanation:

Given data:

Mass of C₆H₁₄O₂ = 16.5 g

Moles of O₂ = 499 mol

Moles of CO₂ = ?

First of all we will write the balance chemical equation.

2C₆H₁₄O₂ + 17O₂ → 14CO₂ + 12H₂O

moles of C₆H₁₄O₂ = mass × molar mass

moles of C₆H₁₄O₂ = 16.5 g × 118 g/mol

moles of C₆H₁₄O₂ = 1947 mol

Now we compare the moles of CO₂ with moles of O₂ and C₆H₁₄O₂ from balance chemical equation.

O₂ : CO₂

17 : 14

499 : 14/17× 499 = 410.9 moles

C₆H₁₄O₂ : CO₂

2 : 14

1947 : 14/2× 1947 = 13629 moles

Oxygen will be limiting reactant so moles of carbon dioxide produced are 410.9 mol.

5 0

3 years ago

Read 2 more answers

What is the average atomic mass of chlorine if the mass of one isotope is 34.97 amu and has a p?er cent abundance of 75.77%. The

pishuonlain [190]

Answer : The average atomic mass of chlorine is, 32.37 amu

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

As we are given that,

Mass of isotope 1 = 34.97 amu

Percentage abundance of isotope 1 = 75.77 %

Fractional abundance of isotope 1 = 0.7577

Mass of isotope 2 = 36.97 amu

Percentage abundance of isotope 2 = 24.23 %

Fractional abundance of isotope 2 = 0.2423

Now put all the given values in above formula, we get:

$\text{Average atomic mass of element}=\sum[(34.97\times 0.7577)+(24.23\times 0.2423)]$

$\text{Average atomic mass of element}=32.37amu$

Therefore, the average atomic mass of chlorine is, 32.37 amu

8 0

3 years ago

What are mountins ussaly made from

Katarina [22]

Answer:

rocks and earth

Explanation:

hope this helps

5 0

3 years ago

Read 2 more answers