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4 years ago

5

what is the formula equation for the reaction between sulfuric acid and dissolved sodium hydroxide if all products and reactants

are in the aqueous or liquid phase?

1 answer:

Rama09 [41]4 years ago

4 0

This reaction would produce salt and water- Sodium Sulphate and Water.

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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A gas sample has volume 3.00 dm3 at 101

gavmur [86]

Answer:

V₂ = 21.3 dm³

Explanation:

Given data:

Initial volume of gas = 3.00 dm³

Initial pressure = 101 Kpa

Final pressure = 14.2 Kpa

Final volume = ?

Solution;

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume

Now we will put the values in formula,

P₁V₁ = P₂V₂

101 Kpa × 3.00 dm³ = 14.2 Kpa × V₂

V₂ = 303 Kpa. dm³/ 14.2 Kpa

V₂ = 21.3 dm³

Explanation:

3 0

3 years ago

Selma made an error while creating a chart to describe the technological design process for a new vacuum. Which best describes h

andre [41]

Answer:

D

Explanation:

just did the test

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4 years ago

Hydrochloric acid is widely used as a laboratory reagent in refining ore for the production of tin and tantalum, and as a cataly

Lyrx [107]

<u>Answer: </u>0.0285 moles of HCl is present in given amount of solution.

<u>Explanation:</u>

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

$\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}}$ .....(1)

Given values:

Molarity of HCl = 0.453 M

Volume of solution = 62.85 mL

Putting values in equation 1, we get:

$0.453mol/L=\frac{\text{Moles of HCl}\times 1000}{62.85}\\\\\text{Moles of HCl}=\frac{0.453\times 62.85}{1000}=0.0285moles$

Hence, 0.0285 moles of HCl is present in given amount of solution.

4 0

3 years ago

How many moles are contained in a 4.67-l sample of gas at 30°c and 199 kpa?

ohaa [14]

Pv=nRT
where,p=199, R(constant)=8.314, V=4.67 T=30C=293K
n=pv/RT=0.38 moles

4 0

3 years ago

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How many grams of magnesium

nexus9112 [7]

Answer:6.68

Explanation:

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3 years ago