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mafiozo [28]
3 years ago
5

How is burning magnesium different from burning methane?

Chemistry
1 answer:
Paha777 [63]3 years ago
3 0
I believe/thought they were very similar due to the fact that they both undergo a process called “oxidation” where they release oxygen into the atmosphere.
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Which diagram best illustrates the difference between distance and<br> displacement?
olga nikolaevna [1]

Answer:

B

Explanation:

not sure

5 0
3 years ago
True or false, In order to obey law of conservation of mass, reactions are arranged to have more atoms of reactants than product
Nesterboy [21]
False - <span>This does not </span>obey<span>the </span>law of conservation of mass<span>. ... created, amount of </span>reactant<span>(s) left over, the quantity of </span>reactants<span> required to </span>make<span> a specified quantity of </span>product. 

8 0
3 years ago
Read 2 more answers
Solid Iron (III) reacts with oxygen gas to form iron (III) oxide, which is the compound we see when rust is present. Based on th
Sunny_sXe [5.5K]

Answer:

Option E is correct. none of the above is correct

Explanation:

Step 1: Data given

Solid Iron (III) = Fe^3+

iron (III) oxide = Fe2O3

Molar mass Fe = 55.845 g/mol

Molar mass Fe2O3 = 159.69 g/mol

Step 2: The balanced equation:

4Fe + 3O2 → 2Fe2O3

4 moles of iron will need 2 moles of oxygen gas to fully react

⇒ This is false 4 moles of iron will need 3 moles of oxygen gas to fully react

B.12 moles of iron, if reacted completely, can produce 8 moles of iron (III) oxide.

⇒ This is false: When 12 moles of iron completely react, we can produce 12/2 = 6 moles of Fe2O3

C.9 moles of oxygen can produce 9 moles of Iron (III) oxide

⇒ This is false; 9 moles of O2 can produce 6 moles of Fe2O3

D.6 moles of oxygen can react completely to produce 6 moles of iron (III) oxide.

⇒ This is false 6 moles of O2 will react completely to produce 4 moles of Fe2O3

E.none of the above

6 0
3 years ago
The atomic mass of Gallium is 69.72 AMU. The masses of the naturally occurring isotopes are 68.9257 AMU and 70.908 AMU for Ga-69
Mashcka [7]

Answer:

40.7% abundance of Ga-71

59.93% abundance of  Ga-69

Explanation:

Given data:

Average atomic mass of Ga = 69.72 amu

Atomic mass of Ga-69 = 68.9257 amu

Atomic mass of Ga-71 = 70.908 amu

Percent abundance of each isotope = ?

Solution;

we know there are two naturally occurring isotopes of Ga.

First of all we will set the fraction for both isotopes

X for the isotopes having mass 68.9257

1-x for isotopes having mass 70.908

we will use the following equation,

68.9257x +  70.908 (1-x) = 69.72

68.9257x +70.908 - 70.908x = 69.72

68.9257x -  70.908x = 69.72 - 70.908

-1.9823x =  - 1.188

x=  1.188/1.9823

x= 0.5993

0.5993 × 100 = 59.93 %

59.93 %  is abundance of Ga-69 because we solve the fraction x.

now we will calculate the abundance of Ga-71.

(1-x)

1 - 0.5993 = 0.4007

0.4007× 100= 40.7 %

40.7 % for Ga-71.

3 0
3 years ago
write a balanced net ionic equation for the following reaction: BaCl2(aq) + H2SO4 (aq) -- BaSO4(s) + HCl (aq)
Fudgin [204]

The  balanced net  equation  for

BaCl2 (aq)  + H2SO4(aq) → BaSO4(s)  + HCl  (aq)  is

 Ba^2+(aq)  +SO4^2- → BaSO4 (s)

 <u><em>Explanation</em></u>

Ionic equation  is a chemical  equation in which  electrolytes  in aqueous  solution are written as dissociated ions.

<u>ionic equation is written using the below steps</u>

Step 1:  <em>write a balanced   molecular equation</em>

 BaCl2 (aq) +H2SO4 (aq)→ BaSO4(s)  +2HCl (aq)

Step 2:   <em>Break all soluble  electrolytes  in to ions</em>

=  Ba^2+ (aq) + 2Cl^-(aq)  + 2H^+(aq) + SO4^2-(aq)→ BaSO4(s)   + 2H^+(aq)  +2Cl^- (aq)


step 3:  <em>cancel the spectator  ions  in both side of equation ( ions which  do not take place in the reaction)</em>

<em> </em><em>    =</em> 2Cl^-  and  2H^+  ions

Step 4: <em>write the final net equation</em>

<em> Ba^2+(aq)  + SO4^2-(aq)→  BaSO4(s</em><em>)</em>

3 0
3 years ago
Read 2 more answers
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