The answer is true they should have both
I believe it's aerobic exercise.
The amount of light between points 1 and 2 is adequate for photosynthesis to occur at a faster rate than cellular respiration. Acidic conditions typically imply that the solution has an excessive concentration of H+, which makes the solution acidic. By dividing the reaction into half-reactions, the balancing process begins.
This indicates that more CO2 is being consumed than is being produced, which makes the problem more straightforward.
The signal will become purple as a result, from yellow. After point 2, light levels are low enough that cellular respiration outpaces photosynthesis, which results in more CO2 being generated than being absorbed and raising the pH of the solution. The indication will become yellow as a result, from purple.
An indicator dye called bromothymol blue (BMB) changes color from blue to yellow when acid is present. The pH of the solution decreases when carbon dioxide is introduced because it produces carbonic acid. When the pH is greater than 7.6, green, between 6.7 and 7.6, and yellow, less than 6, BMB is blue.
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The answer is A.
Neither B nor C make sense, because in a sensible experiment, we dont try to mess up the results or replace results.
