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kondor19780726 [428]
3 years ago
13

What is the amino acid sequence for the mRNA strand CACCCAUGGUGA?

Biology
1 answer:
krek1111 [17]3 years ago
8 0

Answer:

Histidine- Proline- Tryptophan- Stop codon

Explanation:

The mRNA strand in the question is produced as a result of a process called TRANSCRIPTION. However, the mRNA transcript is further used to synthesize an amino acid sequence in a process called TRANSLATION. The mRNA sequence is read in a group of three nucleotide bases called CODON.

Each codon specifies an amino acid which is represented in the GENETIC CODE. In this case, a sequence of mRNA strand is given as: CACCCAUGGUGA

The following codons in the sequence specify the following amino acid:

CAC - Histidine

CCA - Proline

UGG - Tryptophan

UGA - Stop codon

Hence, the amino acid sequence encoded by the given mRNA strand is Histidine- Proline- Tryptophan- Stop codon.

N.B: After a stop codon (UGA, UAA, UAG) is encountered, the translation process stops.

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3 years ago
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The human MN blood type is determined by two codominant alleles, L(M) and L(N). The frequency of L(M) in Eskimos on a small Arct
tatiyna

Answer:

(a) Frequency of M = 0.64

    Frequency of N = 0.04

    Frequency of MN= 0.32

(b)  Expected frequencies of M = 0.648

     Expected frequencies of MN = 0.304

     Expected frequencies of N =  0.048

Explanation:

(a) If random mating takes place in the population, then  the expected frequencies are

f(L(M)) = p = 0.8

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q= 1 - p

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= 0.2

Frequency of M = p^2 = ( 0.8)^2 = 0.64

Frequency of N = q^2 = (1-p)^2 = (1 - 0.8)^2 = (0.2)^2 = 0.04

Frequency of MN = 2pq = 2 * 0.8 * 0.2 = 0.32

(b)

F = inbreeding coefficient = 0.05

f(L(M)L(M)) = p^2 + Fpq = (0.8)^2 + 0.05 * 0.8 * 0.2 = 0.648

f(L(M)L(N)) = 2 pq - 2Fpq = 2 * 0.8 * 0.2 - ( 2 * 0.05 * 0.8 * 0.2) = 0.304

f(L(N)L(N)) = q^2 + Fpq = (0.2)^2 + ( 0.05 * 0.8 * 0.2) = 0.048

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