Applications of fleming hand rule
1 answer:
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Answer:
(a) attached below
(b)
(c)
(d) Ω
(e) and
Explanation:
Given data:
(a) Draw the power triangle for each load and for the combined load.
°
°
≅
≅
The negative sign means that the load 2 is providing reactive power rather than consuming
Then the combined load will be
(b) Determine the power factor of the combined load and state whether lagging or leading.
or in the polar form
°
The relationship between Apparent power S and Current I is
Since there is conjugate of current I therefore, the angle will become negative and hence power factor will be lagging.
(c) Determine the magnitude of the line current from the source.
Current of the combined load can be found by
(d) Δ-connected capacitors are now installed in parallel with the combined load. What value of capacitive reactance is needed in each leg of the A to make the source power factor unity?Give your answer in Ω
Ω
(e) Compute the magnitude of the current in each capacitor and the line current from the source.
Current flowing in the capacitor is
Line current flowing from the source is
Answer:
(a) 0.1509 mm
(b) 0.00525 mm
Explanation:
Stress, is given by
where F is force and A is area and area is given by
hence
where d is the diameter. Substituting 9970 N for F and 10mm=0.01 m for d hence
From the attached stress-strain diagram, the stress of 127 Mpa corresponds to strain of 0.0015 and since strain is given by
where
is the strain,
is elongation and l is original length and making elongation the subject
and substituting strain with 0.0015 and length l with 100.6 mm then
(b)
Lateral strain is given by
and substituting
for
where v is poisson ratio then
and making
the subject then
and substituting 0.35 for v, 0.0015 for strain and 10 mm for d
and the negative sign indicates decrease in diameter
