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dezoksy [38]
4 years ago
11

Determine the Thevenin/Norton Equivalent Circuit with respect to the terminalsa,bas shown in the figure. (Here 1A is an independ

ent current source)

Engineering
1 answer:
melisa1 [442]4 years ago
3 0

Answer:

the the the the the the the

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I want to solve the question
DedPeter [7]

Answer:

yes.

Explanation:

5 0
3 years ago
Read through the solution below. Then, answer the questions that follow.
nlexa [21]

Answer:

In the line marked *, the strategy that was used was renaming a fraction

The expression de-c fills in the orange box.

Explanation:

just did those questions 2020egen

8 0
4 years ago
Read 2 more answers
According to the place-time model of interaction, when people are in the same place, but at different times, this is an example
STALIN [3.7K]

Answer: Shift work communication.

Explanation:

Shift work communication is a type of communication that exist between shift workers, or people at different time zones.

Shift work consists of a three eight hours shift within 24 hours.

Keeping up with a shift work communication requires planning, time management and commitment. It also requires using various communication channels.

3 0
3 years ago
A rotator has a weight of 100lb with a centroidal radius of gyration of 9 in. Determine the moment of inertia about the center o
Ronch [10]

Answer:

8100 lbin²

Explanation:

Moment or inertia is expressed using the formula

I = mr²

M is the mass of the body

r is the radius of gyration

Given

W = 100lb

r = 9in

Required

Moment of inertia

I = Wr²

I = 100(9)²

I = 100×81

I = 8100lbin²

Hence the moment of inertia about the center of gravity for the rotator is

8100 lbin²

8 0
3 years ago
Express the Internal Energy and Entropy as a Function of T and V for a homogeneous fluid. Develop the same relations using the i
DedPeter [7]

Answer:

dU=C_{v} dT+(T(\frac{\beta }{\kappa })  -P)dV

dS=C_{v} \frac{dT}{T} +(\frac{\beta }{\kappa } ) dV

Explanation:

The internal energy is equal to:

dU=C_{v} dT+(T(\frac{\delta P}{\delta T} )_{v} -P)dV

The entropy is equal to:

dS=C_{v} \frac{dT}{T} +(\frac{\delta P}{\delta T} )_{v} dV

If we write the pressure derivative in terms of isothermal compresibility and volume expansivity, we have

\frac{\delta P}{\delta T}=\frac{\beta }{\kappa }

Replacing:

dU=C_{v} dT+(T(\frac{\beta }{\kappa })  -P)dV

dS=C_{v} \frac{dT}{T} +(\frac{\beta }{\kappa } ) dV

4 0
3 years ago
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