1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
stealth61 [152]
2 years ago
8

3. Air at 1 atm and 20 0 C flows tangentially on both sides of a smooth flat plate of width W=10 ft and length L=10 ft in the di

rection of flow (x-direction). The velocity outside the boundary layer is constant at 20 ft/s. a) What is the laminar boundary layer thickness at x=1 ft? b) The boundary layer varies as x to what power? c) If the plate is 100 ft long, does the boundary layer thickness change at 1 ft?
Engineering
1 answer:
8_murik_8 [283]2 years ago
6 0

Answer:

ExplanationAir at 1 atm and 20°C flows tangentially on both sides of a thin, smooth flat plate of ... ... Smooth Flat Plate Of Width W = 10 Ft, And Of Length L 3 Ft In The Direction Of The Flow. The Velocity Outside The Boundary Layer Is Constant At 20 Ft/s.

:

You might be interested in
Refrigerant 134a enters the evaporator of a refrigeration system operating at steady state at -16oC and a quality of 20% at a ve
Dmitry [639]

Answer:

mass flow rate = 0.0534 kg/sec

velocity at exit = 29.34 m/sec

Explanation:

From the information given:

Inlet:

Temperature T_1 = -16^0\ C

Quality x_1 = 0.2

Outlet:

Temperature T_2 = -16^0 C

Quality  x_2 = 1

The following data were obtained at saturation properties of R134a at the temperature of -16° C

v_f= 0.7428 \times 10^{-3} \ m^3/kg \\ \\  v_g = 0.1247 \ m^3 /kg

v_1 = v_f + x_1 ( vg - ( v_f)) \\ \\ v_1 = 0.7428 \times 10^{-3} + 0.2 (0.1247 -(0.7428 \times 10^{-3})) \\ \\  v_1 = 0.0255 \ m^3/kg \\ \\ \\  v_2 = v_g = 0.1247 \ m^3/kg

m = \rho_1A_1v_1 = \rho_2A_2v_2 \\ \\  m = \dfrac{1}{0.0255} \times \dfrac{\pi}{4}\times (1.7 \times 10^{-2})^2\times 6  \\ \\ \mathbf{m = 0.0534 \ kg/sec}

\rho_1A_1v_1 = \rho_2A_2v_2 \\ \\ A_1 =A_2  \\ \\  \rho_1v_1 = \rho_2v_2   \\ \\ \implies \dfrac{1}{0.0255} \times6 = \dfrac{1}{0.1247}\times (v_2)\\ \\ \\\mathbf{\\ v_2 = 29.34 \ m/sec}

3 0
2 years ago
THEME: What is the impact of technology on architecture?
abruzzese [7]

Answer:

With increased technological knowledge and consequent decreased factors of ignorance, the structures have less inert masses and therefore less need for such decoration. This is the reason why the modern buildings are plainer and depend upon precision of outline and perfection of finish for their architectural effect.

8 0
3 years ago
Which of the following are three criteria for creating measurable product attributes?
Vinil7 [7]

Answer:

it A

Explanation:

8 0
3 years ago
Read 2 more answers
.
Gennadij [26K]

Answer:

II

Explanation:

3 0
2 years ago
Wheel diameter 150 mm, and infeed 0.06 mm in a surface grinding operation. Wheel speed 1600 m/min, work speed 0.30 m/s, and cros
gogolik [260]

Answer:

a) the average length per chip is 3 mm

b) the metal removal rate MR is 90 mm³/sec

c) number of chips formed per unit time for the portion of the operation when the wheel is engaged in the work is 4,000,000 chips/min

Explanation:

Given that;

wheel diameter = 150 mm

infeed = 0.06 mm

wheel speed = 1600 m/min = 16000000 mm/s

work speed = 0.30 m/s = 300 mm/s

cross feed = 5 mm

active grits per area = 50 grits/cm²

a)

Average length per chip

Average chip length is given by

Lc = √fd

f is infeed and d is diameter of the wheel

so we substitute

Lc = √( 0.06 × 150

Lc = √ 9

Lc = 3 mm

Therefore the average length per chip is 3 mm

b)

metal removal rate MR is expressed as;

MR = fvc

v is work speed, c is cross feed and f is infeed

so we substitute

MR = 0.06 × 300 × 5

MR = 90 mm³/sec

Therefore the metal removal rate MR is 90 mm³/sec

c)

number of chips formed per unit time is expressed as

No = Vw × c × G

Vw is wheel speed and G is active grits per area

so we substitute

No = 1600000 × 5 × 50/10²

= 4,000,000 chips/min

Therefore number of chips formed per unit time for the portion of the operation when the wheel is engaged in the work is 4,000,000 chips/min

4 0
2 years ago
Other questions:
  • The solid cylinders AB and BC are bonded together at B and are attached to fixed supports at A and C. The modulus of rigidity is
    6·1 answer
  • Estimate the theoretical fracture strength (in MPa) of a brittle material if it is known that fracture occurs by the propagation
    8·1 answer
  • Inspection with considering a variable uses gages to determine if the product is good or bad. True or False?
    15·2 answers
  • A proposed piping and pumping system has 20-psig static pressure, and the piping discharges to atmosphere 160 ft above the pump.
    8·1 answer
  • You are investigating surface hardening in iron using nitrogen gas. Two 5 mm thick slabs of iron are separately exposed to nitro
    10·1 answer
  • An isothermal CSTR with a first order irreversible reaction A â> B (and rA[mol/(ft3*min)] = - 0.5 CA) has a constant flow rat
    13·1 answer
  • The boost converter of Fig. 6-8 has parameter Vs 20 V, D 0.6, R 12.5 , L 10 H, C 40 F, and the switching frequency is 200 kHz. (
    12·1 answer
  • Consider the function f(x)=/x/
    5·1 answer
  • who wants points for now work just put any answer who wants points for now work just put any answer who wants points for now wor
    5·1 answer
  • Question is written in following attached screenshot.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!