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Paha777 [63]
3 years ago
8

If an alloy is formed that is 50 mol% silver and 50 mol% gold, what is the karat number of the alloy?

Chemistry
2 answers:
Allisa [31]3 years ago
7 0
Answer : 12 karat

Explanation : When pure gold is considered to be 24 karat then if its 50 mol% silver and 50 mol% silver then using karat scale calculation;

Karat/24 X 100 = 50 mol% (for gold) in alloy

So, Karat = (50 X 24) / 100 = 12 karat.

Hence the alloy will be of 12 karat.
ladessa [460]3 years ago
7 0

Answer:

Karat number for the alloy = 12

Explanation:

<u>Given:</u>

Mol% gold = 50

Mol% silver = 50

<u>To determine:</u>

The karat number of the alloy

<u>Explanation:</u>

A Karat number is a parameter which is used to describe alloys containing gold based on the % gold in the alloy.

The corresponding formula is:

Percent Gold = \frac{K}{24}*100

where K= Karat number

K = \frac{Percent Gold * 24}{100}=\frac{50*24}{100}=12

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6 0
2 years ago
If a piece of matter changes shape, how does its mass change?
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3 years ago
Calculate the volume in mL of 0.589 M NaOH needed to neutralize 52.1 mL of 0.821 M HCl in a titration.
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Answer:

72.6 mL

Explanation:

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4 0
2 years ago
Determine the percent yield of a reaction that produces 28.65 g of Fe when 50.00 g of Fe2O3 react with excess Al according to th
Luba_88 [7]

Answer:

The percent yield of the reaction is 82%

Explanation:

First step: make the chemist equation.

2 Al (s) + Fe2O3 (s) → 2 Fe (s) + Al2O3 (s)

As the statement says that aluminun is in excess, the limiting reactant is the Fe2O3

Second step: Find out the moles in the reactant.

Molar weight Fe2O3: 159.7 g/m

Mass / Molar weight = moles

50 g /159.7 g/m = 0.313 moles

Third step: Analyse the reaction. 1 mol of Fe2O3 makes 2 moles of Fe.

1 mol Fe2O3 ____ 2Fe

0.313 mol Fe2O3 ____ 0.626 moles

Molar weight Fe = 55.85 g/m

Moles . molar weight = mass

55.85g/m . 0.626m = 34.9 grams

This will be the 100% yield of the reaction but we only made 28.65 g

34.9 g ____ 100%

28.65 g ____ 82.09 %

3 0
3 years ago
Read 2 more answers
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