Answer:
g = 1.11x10⁻⁵Ω.
Explanation:
The membrane conductance (g) can be calculated by dividing membrane current (I) through the driving force (Vm - E) as follows:
<em>where Vm: is the membrane potential and </em><em>: is the equilibrium potential for the ion or reversal potential. </em>
The equilibrium potential for the ion can be calculated using the Nernst equation:
<em>where R: is the gas constant = 8.314 J/K*mol, F: is the Faraday constant = 96500 C/mol, T: is the temperature (K), z: is the ion's charge, [ion]out and [ion]ins: is the concentration of the ion outside and inside, respectively. </em>
Now, we can calculate the membrane conductance (g) using equation (1):
Therefore, the membrane conductance is 1.11x10⁻⁵Ω.
I hope it helps you!
Answer:
5.916x10⁻³ mol OH⁻
Explanation:
The reaction that takes place is:
- H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O
First we <u>calculate the added moles of each reagent</u>, using the <em>given volumes and concentrations</em>:
- H₂SO₄ ⇒ 0.144 M * 27.55 mL = 3.967 mmol H₂SO₄
- KOH ⇒ 0.316 M * 43.84 mL = 13.85 mmol KOH
Now we<u> calculate how many KOH moles reacted with 3.967 mmol H₂SO₄</u>:
- 3.967 mmol H₂SO₄ * = 7.934 mmol KOH
Finally we calculate how many OH⁻ moles remained after the reaction
- 13.85 mmol - 7.934 mmol = 5.916 mmol OH⁻
- 5.916 mmol / 1000 = 5.916x10⁻³ mol OH⁻
It will get hotter, because the molecules create heat when they move around just like us when we run.
Zero...bcz force which acts on this charge is f=qvB q=2uc ,B=2T and v=o
so,f=zero...
Given the information we have V1=20ml V2=35.25ml (V=volume)
M1=15.71g M2= second mass unknown
Set as proportion: V1 V2
----- = -----
M1 M2
20ml 35.25ml
Cross multiply --------- = ------------ THEN 20ml (M2)= (35.25ml)x (15.71g)
15.71g M2 20ml (M2)= 553.7775ml/g
Divide both sides by 20ml to solve for M2.
20ml (M2) 553.7775ml/g
--------------- = ------------------- then M2=27.688875g
20ml 20ml
Second question we need to find volume but we know Volume=Mass/density.
We need to find density first because we have mass=125.4g only given.
Since we are working with the same alcohol we can use the first V1 and M1 to find density=M/V.
Density= M1/V1 Density= 15.71g/20ml then density=0.7855 g/ml
( It would be the same density if we used V2 and M2)
Now we find the volume of 125.4g with a density of 0.7855g/ml
V= M/D V=125.4g/0.7855g/ml then V=159.64ml
Note: Do not round off until you have reached the end of problem. It will give you a better approximation. Also, round to the largest place which in this case was two decimal places. Do not forget unit of measure.