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9966 [12]
2 years ago
13

How many atoms are in four molecules of oxygen gas ​

Chemistry
1 answer:
Dmitrij [34]2 years ago
8 0

Answer:

8 oxygen atoms

Explanation:

One molecule of oxygen gas has two oxygen atoms (O2). If there are four molecules, then we multiply two by four to get 8 atoms.

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A pure substance that is present before a reaction but not after <br> Super Confused
never [62]

Explanation:

Pure subsance is a substance that is made up of only one type of particle - each piece is the same throughout.

Being present before the reaction but not after means it's no the same (it couldve evaporated)

4 0
3 years ago
When forming ions, nitrogen will gain or lose how many electrons, forming a cations or anions with a what charge?
Ann [662]

Answer:

Nonmetals form negative ions (anions). A nitrogen atom must gain three electrons to have the same number of electrons as an atom of the following noble gas, neon. Thus, a nitrogen atom will form an anion with three more electrons than protons and a charge of 3−.

Explanation:

have advanced

8 0
2 years ago
How many atoms and ions does nickel oxide have?
Alex73 [517]

Answer: 1 atom

Explanation:

The loss of the remaining valence electron results in an ion with a +2 charge. The proper way of noting the charges on these ions is to use the systematic name for each ion, nickel (I) for the +1 ion and nickel (II) for the +2 ion.

4 0
2 years ago
Which of the following is the name given to a carbohydrate containing two monomers?
aev [14]
Disaccharide forms when two monomers join.
6 0
2 years ago
Read 2 more answers
A certain drug has a half-life in the body of 3.5h. Suppose a patient takes one 200.Mg pill at :500PM and another identical pill
tekilochka [14]

Answer:

The amount of drug left in his body at 7:00 pm is 315.7 mg.

Explanation:

First, we need to find the amount of drug in the body at 90 min by using the exponential decay equation:

N_{t} = N_{0}e^{-\lambda t}

Where:

λ: is the decay constant = ln(2)/t_{1/2}

t_{1/2}: is the half-life of the drug = 3.5 h

N(t): is the quantity of the drug at time t

N₀: is the initial quantity

After 90 min and before he takes the other 200 mg pill, we have:

N_{t} = 200e^{-\frac{ln(2)}{3.5 h}*90 min*\frac{1 h}{60 min}} = 148.6 mg

Now, at 7:00 pm we have:

t = 7:00 pm - (5:00 pm + 90 min) = 30 min

N_{t} = (200 + 148.6)e^{-\frac{ln(2)}{3.5 h}*30 min*\frac{1 h}{60 min}} = 315.7 mg    

Therefore, the amount of drug left in his body at 7:00 pm is 315.7 mg (from an initial amount of 400 mg).

I hope it helps you!

3 0
2 years ago
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