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Mrrafil [7]
3 years ago
7

In table below, there are descriptions of an experiment on samples of three different chemical compounds. Decide whether the com

pound is ionic or molecular, if you can. If there is not enough information to decide, choose can't decide in the third column.
compound description ionic or molecular
1 Compound 1 is a light gray solid made of
overlapping hexagonal crystals. When heated gently it
starts to soften and develop an unpleasant smell about
50 °C. above room temperature.
2 Compound 2 is a dull white smooth solid which does not
conduct electricity. Applying an ordinary laboratory burner
to the material only makes the substance hot, it does not
otherwise change. In fact, the substance can't be melted
or even softed by any ordinary laboratory equipment.
3 Compound 3 is a clear liquid with a strong pleasantly
fruity smell. If cooled it freezes at about -10 °C. In the
solid state it does not conduct electricity.
Chemistry
1 answer:
likoan [24]3 years ago
7 0

Answer:

Compound 1 is molecular

Compound 2 is ionic

Compound 3 can't really be decided

Explanation:

A molecular substance does not conduct electricity, has very low melting and boiling points and is held together by very weak intermolecular forces.

An ionic substance conducts electricity in solution or in molten state but never in the pure solid state, has a high melting and boiling point and has a dull appearance most times.

Compounds 1 shows the properties of molecular substances hence it are designated as such.

On the other hand, compound 2 shows the properties of an ionic substance and is also designated as such.

We can't really decide on compound 3 because it shows some properties of ionic substances and some properties of molecular substances.

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This decomposition is first order with respect to phosphine, and has a half‑life of 35.0 s at 953 K. Calculate the partial press
Solnce55 [7]

Answer:

0.57 atm

Explanation:

When a a reaction is first order, we have from calculus the following relation:

ln[A]t/[A]₀ = - kt

where [A]t is the concentration of A ( phosphine in this case ) after a time, t

           [A]₀ is the initial concentration of A

           k is the rate constant, and

           t is the time

We also know that for a first order reaction

           k = 0.693/ t 1/2

wnere t 1/2 is the half-life.

This equation is derived for the case when A]t/= 1/2 x [A]₀ which occurs at the half-life.

Thus, lets first find k from the half life time, and then solve for t = 70.5 s

k = 0.693 /  35.0 s = 0.0198 s⁻¹

ln [ PH₃ ]t / [ PH₃]₀ = - kt

from the ideal gas law we know pV = nRT, so the volumes cancel:

ln (pPH₃ )t / p(PH₃)₀ = - kt

taking inverse log to both sides of the equation:

(pPH₃ )t / p(PH₃)₀  = - kt

thus:

(pPH₃ )t  = 2.29 atm x e^(- 0.0198 s⁻¹ x 70.5 s ) = 0.57 atm

3 0
4 years ago
HELP ASAP PLEASE!!!! 30 POINTS
valentina_108 [34]

Answer:

it's option c

Explanation:

because if I'm not wrong I have learned these type of questions back 11 and I remember that rutherfords observation was few alpha particles were deflected by small angles.

5 0
3 years ago
Read 2 more answers
Calculate the pH of: (a) 0.1M HCl; (b) 0.1M NaOH; (c) 3 X 10% M HNO3; (d) 5 X 10-10 M HCIO.; and (e) 2 x 10-8 M KOH.
Shtirlitz [24]

Answer:

(a) pH = -Log (0.1M) = 1

(b) pH = -Log (10^{-13}M) = 13

(c) pH = -Log (3x10^{-3}M) = 2.5

(d) pH = -Log (4.93x10^{-10}M) = 9.3

(e) pH = -Log (5^{-7}M) = 6.3

Explanation:

To calculate de pH of an acid solution the formula is:

pH = -Log ([H^{+}]) = 1

were [H^{+}] is the concentration of protons of the solution. Therefore it is necessary to know the concentration of the protons for every solution in order to solve the problem.

(a) and (c) are strong acids so they dissociate completely in aqueous solution. Thus, the concentration of the acid is the same as the protons.

(b) and (e) are strong bases so they dissociate completely in aqueous solution too. Thus, the concentration of the base is the same as the oxydriles. But in this case it is necessary to consider the water autoionization to calculate the protons concentration:

K_{w} =[H^{+} ][OH^{-}]=10^{-14}

clearing the [H^{+} ]

[H^{+} ]=\frac{10^{-14}}{[OH^{-}]}

(d) is a weak base so it is necessary to solve the equilibrium first, knowing Ka=3.24x10^{-8}

The reaction is HClO  →  H^{+} + CO^{-} so the equilibrium is

Ka=3.24x10^{-8}=\frac{x^{2}}{5x10^{-8}-x}

clearing the <em>x</em>

{x^{2}={1.62x10^{-17}-3.24x10^{-8}x}

x=[H^{+}]=4.93x10^{-10}

6 0
4 years ago
An equilibrium is not changed by a change in pressure.<br><br> True<br> OR<br> False
geniusboy [140]
It IS changed. When there is pressure, itll move along to the side of where there are fewer moles of gas in the reaction. Decrease in pressure causes it to shift to the side with more moles of gas. So, false, it IS in fact changed
5 0
3 years ago
Some countries are considering putting something in explosive materials to help track where they came from. What tool would you
cestrela7 [59]

Answer:

The answer would be A: satellite and GPS system

Explanation:

This is the answer because you can track someone using the GPS system or you can detect heat on a satelite

7 0
3 years ago
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