Answer:
v_f = 10.85 m/s
Explanation:
We will apply the law of conservation of momentum here:

where,
m₁ = mass of roller skater = 47 kg
m₂ = mass of bag = 6 kg
v_1i = initial speed of roller skater = 12 m/s
v_2i = initial speed of the bag = 0 m/s
v_1f = final speed of the roller skater = ?
v_2f = final speed of the bag = ?
Both the bag and the skater will have same speed at the end because kater is carrying the bag:
v_1f = v_2f = v_f
Therefore, the equation will become:

<u>v_f = 10.85 m/s</u>
Answer:
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A. A control group is given the experimental treatment.
Answer:
Explanation:
Work done by mountain climber against his weight
= mgH
= 70.5 X 9.8 X 365
= 252178.5 J
Power = work done / time taken to do work
= 252178.5 / (49 x 60 )
= 85.775 J/s
= 85.775 W .