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sweet [91]
2 years ago
12

Please help me with my quiz

Physics
1 answer:
Oduvanchick [21]2 years ago
8 0

Answer:

matter: A

data: E

variable: C

Controlled: D

Physical: B

Explanation:

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Create a ray diagram for eyeglasses that contain a diverging lens. Assume you are looking at a 2 cm tall object that is 4 cm fro
k0ka [10]

The ray diagram for the given object consists of 2 cm height of object, 4 cm object distance and 3 cm focal length.

<h3>Image formed by a diverging lens</h3>

Diverging lens is called a concave lens. The working of the lens is dependent on the refraction of the light rays as they pass through the lens.

Image formed by a diverging lens is always virtual, erect and diminished; smaller than the object and is located on the same side of the lens as the object.

The ray diagram for the given object is presented in the image in the diagram.

  • Object height = 2 cm
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Learn more about diverging lens here: brainly.com/question/3140453

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3 years ago
A space vehicle accelerates uniformly from 85 m/s at t = 0 to 164 m/s at t = 10.0 s .How far did it move between t = 2.0 s and t
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First, we have a change in the velocity from 85 to 164 m/s in 10 sec.

Then, we calculate the <u>acceleration </u>as:

a=\frac{v_{f}-v_{i} }{t} =\frac{164-85}{10}=7.9 m/s^2

Hence we need to calculate the velocity of the space vehicle at t = 2 sec using the first equation of motion:

v_{f}=v_{i}+at=85+7.9*2=100.8m/s

Then, using the second equation of motion to calculate the distance:

d=v_{i}  t+\frac{1}{2}at^2

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