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zubka84 [21]
3 years ago
10

A box of 5kg is lifted 10m. how much work is done?

Physics
1 answer:
Black_prince [1.1K]3 years ago
7 0

Answer:

500 [J].

Explanation:

1) the rule is: W=E₂-E₁, where W - required work, E₂ - energy after lifting, E₁ - energy before lifting;

2) energy: E=mgh, where m - mass, g≈10 [N/kg], h - height;

3) then the required work:

W=mgh₂-mgh₁=m*g*(h₂-h₁), where (h₂-h₁)=10 [m.]

finally, W=5*10*10=500 [J].

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g In 1956, Frank Lloyd Wright proposed the construction of a mile-high building in Chicago. Suppose the building had been constr
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To solve this problem it is necessary to apply the concepts related to acceleration due to gravity, as well as Newton's second law that describes the weight based on its mass and the acceleration of the celestial body on which it depends.

In other words the acceleration can be described as

a = \frac{GM}{r^2}

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M = Mass of Earth

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da = -2\frac{GM}{r^3}dr

At the same time since Newton's second law we know that:

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Finally to find the change in weight it is necessary to differentiate the Force with respect to the acceleration, then:

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dF_W = -2(m\frac{GM}{r^2})(\frac{dr}{r})

dF_W = -2F_W(\frac{dr}{r})

But we know that the total weight (F_W) is equivalent to 600N, and that the change during each mile in kilometers is 1.6km or 1600m therefore:

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4 0
4 years ago
Jon's bathtub is rectangular and its base is 18 ft2. (a) How fast is the water level rising if Jon is filling the tub at a rate
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Volume of the bath tub = (Area of base) × (height)

Area of base = 18 ft² (constant)

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V = 18h

(dV/dt) = 18 (dh/dt)

If (dV/dt) = 0.2 ft³/s

0.2 = 18 (dh/dt)

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6 0
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Answer:

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We know that weight is given by W = mg

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