Answer:
Average atomic mass = 79.9035 amu.
The given element is bromine.
Explanation:
Given data:
Mass of 1st isotope = 78.9183 amu
Percent abundance of 1st isotope = 50.69%
Mass of 2nd isotope = 80.9163 amu
Percent abundance of 1st isotope = 49.31%
Average atomic mass = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (50.69×78.9183 )+(49.31× 80.9163) /100
Average atomic mass = 4000.3686+ 3989.9828 / 100
Average atomic mass = 7990.3514 / 100
Average atomic mass = 79.9035 amu.
The given element is bromine.
Mass of 1 centigram is equal to 0.01 grams
So, option C is your answer!
Hope this helps!
Answer:
I think it's b.
Explanation:
Because solubility increased by temperature.
Hi there!
The answer to this is simple, the answer is just a dot. (Really, that's it)
Hope this helps! ☺♥