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mario62 [17]
4 years ago
6

3cu(s) + 8hno3(aq) ——> 3cu(no3)2(aq) + 2no(g) + h2o(l) whichr eactan is the reducing agent?

Chemistry
1 answer:
igor_vitrenko [27]4 years ago
6 0
...0.............I..V.-II..............II...V.-II...........II..-II.......I...-II
3Cu(s) + 8HNO3 ---> 3Cu(NO3)2 + 2NO + 4H2O

V.....................II
N + 3e -----> N >> reduction
HNO3 - oxidizing agent

..0...........II
Cu ----> Cu + 2e >> oxidation
Cu - reducing agent
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How can you increase the amount of work done when you lift a book explain
Gnoma [55]
<h2>Work done = mgh </h2>

Explanation:

  • In this case, while lifting the book we are working against the force of gravity.

Using the Newton's laws, we can find the force F required for lifting the book having mass (m) and acceleration due to gravity (g) that is ;

  • F = mg

and, the change in the position of the book that is Δx (Height)

→ Δx = Final position - Initial position

which is only the height, then the amount of work done will be calculated by :

W= mgh

  • Where W = Work Done

m = Mass of the Body

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h = Height of Body being displaced

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3 years ago
What is the pH of a 2.10 x 10⁻⁶ M solution of HCl?<br>​
Delvig [45]

Answer:

pH = 5.7

Explanation:

pH = -log[H^+]  

For HCl pH = -log[HCl] = - log [2.10 x 10⁻⁶ ] = 5.7

5 0
3 years ago
How many hydrogen molecules are there in 1 ton of hydrogen?​
zaharov [31]
Hydrogen gas(H2) has a molar mass of 2 g. Molar mass of a substance is defined as the mass of 1 mole of that substance. And by 1 mole it is meant a collection of 6.022*10^23 particles of that substance.

So number of moles of H2 are 0.5 in this case. And thus it means there are (6.022*10^23)*0.5 particles( here they are molecules) in 1g of H2.
6 0
3 years ago
Consider 100.0 g samples of two different compounds consisting only of carbon and oxygen. One compound contains 27.2 g of carbon
Pani-rosa [81]

<u>Answer:</u> The ratio of carbon in both the compounds is 1 : 2

<u>Explanation:</u>

Law of multiple proportions states that when two elements combine to form two or more compounds in more than one proportion. The mass of one element that combine with a given mass of the other element are present in the ratios of small whole number. For Example: Cu_2O\text{ and }CuO

  • <u>For Sample 1:</u>

Total mass of sample = 100 g

Mass of carbon = 27.2 g

Mass of oxygen = (100 - 27.7) = 72.8 g

To formulate the formula of the compound, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{27.2g}{12g/mole}=2.26moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{72.8g}{16g/mole}=4.55moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 2.26 moles.

For Carbon = \frac{2.26}{2.26}=1

For Oxygen  = \frac{4.55}{2.26}=2.01\approx 2

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : O = 1 : 2

Hence, the formula for sample 1 is CO_2

  • <u>For Sample 2:</u>

Total mass of sample = 100 g

Mass of carbon = 42.9 g

Mass of oxygen = (100 - 42.9) = 57.1 g

To formulate the formula of the compound, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{42.9g}{12g/mole}=3.57moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{57.1g}{16g/mole}=3.57moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.57 moles.

For Carbon = \frac{3.57}{3.57}=1

For Oxygen  = \frac{3.57}{3.57}=1

<u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : O = 1 : 1

Hence, the formula for sample 1 is CO

In the given samples, we need to fix the ratio of oxygen atoms.

So, in sample one, the atom ratio of oxygen and carbon is 2 : 1.

Thus, for 1 atom of oxygen, the atoms of carbon required will be = \frac{1}{2}\times 1=\frac{1}{2}

Now, taking the ratio of carbon atoms in both the samples, we get:

C_1:C_2=\frac{1}{2}:1=1:2

Hence, the ratio of carbon in both the compounds is 1 : 2

8 0
3 years ago
How do you tell if elements have similar chemical properties periodic table?
Oksi-84 [34.3K]
Whether or not they are within the same group (vertical columns) within the periodic table, determines similarity of chemical properties.
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