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Sindrei [870]
3 years ago
6

The table shows Kayden's quiz scores for a semester. What are the mean and the standard deviation, rounded to the nearest hundre

dth, for the quiz data?
45 48 42 47 43

Mean =

Standard deviation =
Mathematics
1 answer:
Rudiy273 years ago
8 0

Answer:

The mean is of 45.

The standard deviation is 2.28.

Step-by-step explanation:

The mean is the sum of all values divided by the number of values.

The standard deviation is the square root of the sum of the difference squared between each value and the mean, and divided by the number of values.

Mean:

M = \frac{45 + 48 + 42 + 47 + 43}{5} = 45

The mean is of 45.

Standard deviation:

M = \sqrt{\frac{(45-45)^2 + (48-45)^2 + (42-45)^2 + (47-45)^2 + (43-45)^2}{5}} = 2.28

The standard deviation is 2.28.

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Answer:

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3 years ago
Sasha solved an equation, as shown below: Step 1: 8x = 56 Step 2: x = 56 – 8 Step 3: x = 48 Part A: Is Sasha's solution correct
bekas [8.4K]
Incorrect, she should have divided both sides by 8. The answer should be x=7. There is only 1 solution to the equation because x is raised to the first degree. It is not a polynomial equation so there won't be more than 1 answer to the equation.
4 0
4 years ago
Simplify (h^2)^-3 this equation
andrew-mc [135]

Step-by-step explanation:

By Law of Indices, (a^m)^n = a^(mn).

Hence (h²)^(-3) = h^(-6) or 1/h⁶.

6 0
3 years ago
Read 2 more answers
Consider the expression 16y^2 . Select the correct statement:
tiny-mole [99]

Step-by-step explanation:

Given expression is:

16y^2

We will solve each statement one by one to see which statements are correct.

<u>If y=3/4, the values of 16y^2 is 12</u>

Putting y = 3/4 in expression

16y^2 = 16 *(\frac{3}{4})^2 = 16 * \frac{9}{16} = 9

<u>If y=1/4, the values of 16y^2 is 2</u>

Putting y = 1/4 in expression

<u></u>16y^2 = 16 *(\frac{1}{4})^2 = 16 * \frac{1}{16} = 1<u></u>

<u></u>

<u>If y=3/8, the values of 16y^2 is 4/9</u>

Putting y = 3/8 in expression

<u></u>16y^2 = 16 *(\frac{3}{8})^2 = 16 * \frac{9}{64} = \frac{9}{4}<u></u>

<u></u>

<u>If y=1/8, the values of 16y^2 is 1/4</u>

Putting y = 1/8 in expression

<u></u>16y^2 = 16 *(\frac{1}{8})^2 = 16 * \frac{1}{64} = \frac{1}{4}<u></u>

<u></u>

<u></u>

<u>If y=2/3, the values of 16y^2 is 3/4</u>

Putting y = 2/3 in expression

<u></u>16y^2 = 16 *(\frac{2}{3})^2 = 16 * \frac{4}{9} = \frac{64}{9}<u></u>

<u></u>

<u>Hence,</u>

The correct statement is:

If y=1/8, the values of 16y^2 is 1/4

Keywords: Expressions, variables

Learn more about expressions at:

  • brainly.com/question/10772025
  • brainly.com/question/10879401

#LearnwithBrainly

7 0
3 years ago
4. Make up a system of equations with infinite<br> solutions
Taya2010 [7]

Answer:

\left \{ {{x+y=1} \atop {2x+2y=2}} \right.

Step-by-step explanation:

As long as the two equations represent the same straight line on the coordinate plane (they overlap), there will be infinite many intersections and infinite number of solutions.

6 0
3 years ago
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