Area of sector = area of circle * ratio that the sector takes up AoS = Pi*r^2 * 255/360 = Pi * 13.4^2 (255/360) = Pi * 179.56 (0.708333333) = Pi * 127.188333 = 399.573933 ~ 399.6 Units Sqaured
x = arctan(-√3/3) = -π/6 . . . . use the inverse tangent function to find x
This is the value in the range (-π/2, π/2). The tangent function repeats with period π, so the set of values of x that will satisfy this equation is ...
