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Marat540 [252]
3 years ago
12

Picture attached for question​

Mathematics
1 answer:
Tema [17]3 years ago
5 0
<h3><u>Explanation</u></h3>
  • Properties of Exponent

{a}^{ \frac{m}{n} }  =  \sqrt[n]{ {a}^{m} }

  • Convert the expressions from radical to exponent form.

9 \sqrt[4]{ {t}^{3} }  \times 7 \sqrt[3]{ {t}^{2} }  \\ 9( {t}^{ \frac{3}{4} } ) \times 7( {t}^{ \frac{2}{3} } )

  • Simplify the expression by multiplying.

63( {t}^{ \frac{3}{4} }  \times  {t}^{ \frac{2}{3} } )  = 63( {t}^{ \frac{3}{4}+\frac{2}{3} } ) \\ 63( {t}^{ \frac{9}{12} + \frac{8}{12} } ) \\ 63( {t}^{ \frac{17}{12} } )Answer[tex] \large \boxed {63 {t}^{ \frac{17}{12} } }

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Account a and b each start with $400. If account a earn $45 each year and account b earns 5% of its value each year when will ac
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Answer:  T>2.185 year

Step-by-step explanation:

A=P\left ( 1+R/100\right )^{T}

A=Amount ,P=Principle , R=Rate , T=Time

CI=compound interest

CI=A-P

P=400\$  for each a and b

account earn each year by a=45\$

account b earns  5%%

find the time the value of b is more

45

445

445/400

\ln \left ( 445/400 \right )

.106609735

=2.1850

T>2.185 year

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3 years ago
20 POINTS .. HELLLPPP !!! Thanks and ASAP, please!!
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Step-by-step explanation:

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3 years ago
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Write an expression for "10 multiplied by u."
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Answer:

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10 multiplied by u is equivalent to 10u

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The quadratic equation h(t)=-16.1t^2+150 models a balls height,in feet, over time, in seconds, after it is dropped from a 15 sto
Nat2105 [25]
h(t)=-16.1t^{2}+150. \newline\frac{d}{dt}[h(t)=-16.1t^{2}+150] = h'(t) = -\frac{161}{10} \cdot \frac{d}{dt}[t^{2}] + \frac{d}{dt}[150] = 0-\frac{161\cdot2t}{10} = -\frac{161t}{5} = -32.2t \Rightarrow t = 32.2 \ s.
8 0
4 years ago
A variable force of 3x−2 pounds moves an object along a straight line when it is x feet from the origin. Calculate the work done
Verdich [7]

Answer:

2.70J.

Step-by-step explanation:

We have been given that a variable force of 3x^{-2} pounds moves an object along a straight line when it is x feet from the origin.  We are asked to find the work done in moving the object from x = 1 ft to x = 10 ft.

We know that dW=Fdx, where F represents force.

dW=3x^{-2}dx

Now, we will integrate both sides of equation as:

\int\limits{dw} =\int\limits^{10}_1 {3x^{-2} \, dx

Take the constant out:

\int\limits{1dw} =3\int\limits^{10}_1 {x^{-2} \, dx

w =3\int\limits^{10}_1 {x^{-2} \, dx

Upon applying power rule of integrals, we will get:

w =3\/[ \frac{x^{-2+1}}{-2+1} ]^{10}_1

w =3[ \frac{x^{-1}}{-1} ]^{10}_1

w =3[ -\frac{1}{x} ]^{10}_1

w =3[ -\frac{1}{10} -(-\frac{1}{1})]

w =3[ -\frac{1}{10}+\frac{10}{10})]

w =3[\frac{9}{10}]

w=2.70

Therefore, the work done by the object is 2.70J.

8 0
3 years ago
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