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Vitek1552 [10]
3 years ago
10

[8.01] Factor completely: -6m2 + 18m - 36 (4 points)

Mathematics
1 answer:
sdas [7]3 years ago
5 0
The answer is <span>-6(m2 - 3m + 6)
</span>
-6m2 + 18m - 36 = - (6m2 - 18m + 36)
                            = - (6m2 - 6*3m + 6*6)
                            = -6(m2 - 3m +6)
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In the figure at the right what is m &lt; 1 if m &lt; 3= 70 degrees
Arturiano [62]
<h2>○=> <u>Correct option</u> :</h2>

\color{plum}\tt\bold{(D)  \: 70}

<h3>○=> <u>Steps to derive correct option</u> :</h3>

Angle 1 and angle 3 are vertically opposite angles.

We know that :

▪︎ Vertically opposite angles are always equal.

Which means :

Angle 1 = Angle 3

Thus, the measure of angle 3 = 70°

▪︎Therefore, the correct option is (D) 70

3 0
3 years ago
I need this know please i will give brainliest
Olegator [25]

Answer:

b,,,,,d

Step-by-step explanation:

number of bags times how much it carries so the result equals kg hold

so we must the number 10 always so substitute in each equation to get the number 10

6 0
3 years ago
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Which integer is the smallest? A. -84 B. -4 OC. 34 OD. 24 Advanced Placement, AP AP Central", College Board", and SAT are tradem
kipiarov [429]

Answer: B -4

Step-by-step explanation: I think it is B because -4 is smaller than A,C and D.

7 0
2 years ago
A 1-pound box of candy cost $4.00. What was the cost<br> per ounce (1 pound 16 ounces)?
vodka [1.7K]

Answer:

I think its $1 every 4 oz

Step-by-step explanation:

Basing this off that 4 * 4 is 16

5 0
3 years ago
Match the parabolas represented by the equations with their vertices. y = x2 + 6x + 8 y = 2x2 + 16x + 28 y = -x2 + 5x + 14 y = -
GaryK [48]

Consider all parabolas:

1.

y = x^2 + 6x + 8,\\y=x^2+6x+9-9+8,\\y=(x^2+6x+9)-1,\\y=(x+3)^2-1.

When x=-3, y=-1, then the point (-3,-1) is vertex of this first parabola.

2.

y = 2x^2 + 16x + 28=2(x^2+8x+14),\\y=2(x^2+8x+16-16+14),\\y=2((x^2+8x+16)-16+14),\\y=2((x+4)^2-2)=2(x+4)^2-4.

When x=-4, y=-4, then the point (-4,-4) is vertex of this second parabola.

3.

y =-x^2 + 5x + 14=-(x^2-5x-14),\\y=-(x^2-5x+\dfrac{25}{4}-\dfrac{25}{4}-14),\\y=-((x^2-5x+\dfrac{25}{4})-\dfrac{25}{4}-14),\\y=-((x-\dfrac{5}{2})^2-\dfrac{81}{4})=-(x-\dfrac{5}{2})^2+\dfrac{81}{4}.

When x=2.5, y=20.25, then the point (2.5,20.25) is vertex of this third parabola.

4.

y =-x^2 + 7x + 7=-(x^2-7x-7),\\y=-(x^2-7x+\dfrac{49}{4}-\dfrac{49}{4}-7),\\y=-((x^2-7x+\dfrac{49}{4})-\dfrac{49}{4}-7),\\y=-((x-\dfrac{7}{2})^2-\dfrac{77}{4})=-(x-\dfrac{7}{2})^2+\dfrac{77}{4}.

When x=3.5, y=19.25, then the point (3.5,19.25) is vertex of this fourth parabola.

5.

y =2x^2 + 7x +5=2(x^2+\dfrac{7}{2}x+\dfrac{5}{2}),\\y=2(x^2+\dfrac{7}{2}x+\dfrac{49}{16}-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x^2+\dfrac{7}{2}x+\dfrac{49}{16})-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x+\dfrac{7}{4})^2-\dfrac{9}{16})=2(x+\dfrac{7}{4})^2-\dfrac{9}{8}.

When x=-1.75, y=-1.125, then the point (-1.75,-1.125) is vertex of this fifth parabola.

6.

y =-2x^2 + 8x +5=-2(x^2-4x-\dfrac{5}{2}),\\y=-2(x^2-4x+4-4-\dfrac{5}{2}),\\y=-2((x^2-4x+4)-4-\dfrac{5}{2}),\\y=-2((x-2)^2-\dfrac{13}{2})=-2(x-2)^2+13.

When x=2, y=13, then the point (2,13) is vertex of this sixth parabola.

3 0
3 years ago
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