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bixtya [17]
4 years ago
10

The sum of the two digits of a number is 9. If the tens digit is one-half the units digit, what is the number? Let t = the tens

digit, u = the units digit, and t + u = 9. Which of the following equations would complete the system?
Mathematics
2 answers:
ollegr [7]4 years ago
8 0

Answer:t=\frac{u}{2}

Step-by-step explanation:

First equation t+u=9

Second equation t = \frac{u}{2} since the number in the tens position is one half of the one in the units. So if you divide u by two, you should have one t, as the equation states

soldi70 [24.7K]4 years ago
3 0
The second condition tells you that t is half the size of u, so t=\dfrac12u, which could be rewritten in several ways. In standard form, that would be 2t-u=0.
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Find an exact value cos(19pi/12)
dmitriy555 [2]

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Substituting x=\frac{19\pi}{12}

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0.0007716049 as a fraction
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To write 0.0007716049 as a fraction you have to write 0.0007716049 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.

0.0007716049 = 0.0007716049/1 = 0.007716049/10 = 0.07716049/100 = 0.7716049/1000 = 7.716049/10000 = 77.16049/100000 = 771.6049/1000000 = 7716.049/10000000 = 77160.49/100000000 = 771604.9/1000000000 = 7716049/10000000000

so your answer is: 7716049/10000000000

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