1) Balanced chemical equation
4NH3(g) + 5O2(g) ---> 4NO(g) + 6H2O(g)
2) State the molar ratios
4 mol NH3 : 5 mol O2 : 4 mol NO : 6 mol H2O
3) Convert 88.9 g of ammonia to moles, using the molar mass
molar mass of NH3 = 14 g/mol + 3 * 1 g/mol = 17 g/mol
number of moles = mass in grams / molar mass = 88.9 g / 17 g/mol = 5.23 mol NH3
4) Make the proportion
4 mol NO / 4 mol NH3 = x / 5.23 mol NH3=> x = 5.23 mol NO
5) Convert 5.23 mol NO to grams
molar mass NO = 14 g/mol + 16g/mol = 30 g/mol
mass = number of moles * molar mass = 5.23 mol * 30 g/mol = 156.9 g ≈ 157 g
Answer: 157 grams
Answer:
0.89 times
Explanation:
Let the initial volume of the tank be V.
Finally, we shall determine how much larger the final volume of the gas will be. This is illustrated below:
Initial pressure (P₁) = 130 kPa
Initial volume (V₁) = V
Final pressure (P₂) = 145.5 kPa
Final volume (V₂) =?
P₁V₁ = P₂V₂
130 × V = 145.5 × V₂
130V = 145.5 × V₂
Divide both side by 145.5
V₂ = 130V / 145.5
V₂ = 0.89V
Therefore, the final volume of gas will be 0.89 times the initial volume.
Incomplete combustion<span> occurs when the supply of air or oxygen is poor. Water is still produced, but carbon monoxide and carbon are produced instead of carbon dioxide</span>
Magma in quiet eruptions has a low content in silica , while in explosive eruptions, it has a high Content in silica. A volcano that erupts quietly has magma that is low in silica. Low-silica magma has low viscosity and flows easily. A volcano that erupts explosively has magma that is high in silica. High-silica magma has high viscosity, making it thick and sticky, thus it flows slowly.
