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Paladinen [302]
2 years ago
10

Be sure to answer these questions in your journal entry: • How long was the journey to Earth? • How fast did you travel? • Was y

our speed affected when you entered Earth’s atmosphere? If so, how? • Was your speed affected when you traveled through the glass of the window? If so, how? • What was the journey like to get to the retina? PLZ HELP ME

Chemistry
1 answer:
damaskus [11]2 years ago
3 0

Answer: What you doing

Explanation:

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El sol es la estrella más grande
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Schb

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3 years ago
What, if anything is wrong with the model of the solar system shown below ? Give me a big or small answer
jekas [21]

Answer:

the sun is supposed to in the middle instead of earth since the planets rotate around the sun. on the side Here are the planets listed in order of their distance from the Sun:

Mercury: ...

Venus: ...

Earth: ...

Mars: ...

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Uranus:

<h2>PLEASE GIVE ME BRAINLIEST !! :)</h2>
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3 years ago
At what pH are the moles of acid and base equal?
mihalych1998 [28]

Answer:

7

Explanation:

(Note: for a strong acid and strong base titration the equivalence point is at a pH=7. This is because at this point you have equal moles of added base as acid in the original solution. Therefore at the equivalence point the solution has formed a neutral salt and the pH is 7).

5 0
2 years ago
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Drag force is directly proportional to ______. velocity. thrust shorter and faster blades longer and slower blades
aniked [119]

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Drag force is directly proportional to squared velocity

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googl e

3 0
2 years ago
The following reaction produces ethanoic acid (CHACOOH) from methanol (CH3OH) and carbon
tigry1 [53]

Answer:

\boxed{\text{300 g}}

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

M_r:         32                          60

           CH₃OH + CO ⟶ CH₃COOH

m/g:        160

(a) Moles of CH₃OH

\text{Moles of CH$_{3}$OH} = \text{160 g CH$_{3}$OH }\times \dfrac{\text{1 mol CH$_{3}$OH }}{\text{32 g CH$_{3}$OH}}= \text{5.00 mol CH$_{3}$OH}

(b) Moles of CH₃COOH

\text{Moles of CH$_{3}$COOH} = \text{5.00 mol CH$_{3}$OH } \times \dfrac{\text{1 mol CH$_{3}$COOH}}{\text{1 mol CH$_{3}$OH }} = \text{5.00 mol CH$_{3}$COOH}

(c) Mass of CH₃COOH

\text{Mass of CH$_{3}$COOH} =\text{5.00 mol CH$_{3}$COOH} \times \dfrac{\text{60 g CH$_{3}$COOH}}{\text{1 mol CH$_{3}$COOH}} = \textbf{300 g CH$_{3}$COOH}\\\\\text{The maximum mass of ethanoic acid that can be produced is $\boxed{\textbf{300 g}}$}

3 0
3 years ago
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