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bogdanovich [222]
2 years ago
10

A 15.0-kg child descends a slide 2.40 m high and reaches the bottom with a speed of 1.10 m/s .

Physics
1 answer:
pickupchik [31]2 years ago
7 0

The thermal energy that is generated due to friction is 344J.

<h3>What is the thermal energy?</h3>

Now we know that the total mechanical energy in the system is constant. The loss in energy is given by the loss in energy.

Thus, the kinetic energy is given as;

KE = 0.5 * mv^2 =0.5 * 15.0-kg * (1.10 m/s)^2 = 9.1 J

PE = mgh = 15.0-kg * 9.8 m/s^2 *  2.40 m = 352.8 J

The thermal energy is; 352.8 J - 9.1 J = 344J

Learn more about thermal energy due to friction:brainly.com/question/7207509

#SPJ1

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The wires leading to and from a 0.12-mm-diameter lightbulb filament are 1.5 mm in diameter. The wire to the filament carries a c
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Answer:

The current in the filament is 0.81 A

Explanation:

Given :

Diameter of wire d_{1} =  0.12 \times 10^{-3} m

Diameter of filament d_{2} = 1.5 \times 10^{-3} m

Current density J = 4.6 \times 10^{5} \frac{A}{m^{2} }

From the formula of current density,

   J = \frac{I}{A}

Where A = area = \frac{\pi d^{2} }{4}

Current in the filament is given by,

   I = JA

Area of filament is given by A = \pi \frac{(1.5 \times 10^{-3} )^{2} }{4}

  A = 1.76 \times 10^{-6}

Put value of A in above equation,

  I = 4.6 \times 10^{5} \times 1.76 \times 10^{-6}

  I = 0.81 A

Therefore, current in the filament is 0.81 A

4 0
3 years ago
Review Problem. A light string with a mass per unit length of 8.20 g/m has its ends tied to two walls separated by a distance eq
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Answer:

The answer is 'D' none

Explanation:

In the figure shown we have

2Tsin(\theta )=mg\\\\\therefore T=\frac{mg}{2sin(\theta )}

From the figure we can see that

cos(\theta )=\frac{\frac{3L}{8}}{\frac{L}{2}}\\\\\therefore \theta =cos^{-1}(\frac{3}{4})\\\\sin(\theta )=\frac{\sqrt{7}}{4}

Thus value of tension be will be

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Allisa [31]

i hope it helped thanks

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A 13.0-V battery is connected in series with a switch, resistor and coil. If the circuit's time constant is 1.20 ´ 10-4 s and th
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Answer:

R = 5.20 Ω,    L = 6.24 10⁻⁴ H

Explanation:

The current in an RL circuit is

           I = \frac{E}{R} \ (1- e^{- t/ \tau } )

           τ = L / R

In the problem they indicate the value of the voltage, the current and the time constant, for which the resistance must be found

         

The stable current is when enough time has passed (t »τ) after closing the circuit, therefore the exponential term is very small and we can neglect it.

            I = E / R

            R = E / I

let's calculate

            R = 13.0 / 2.50

            R = 5.20 Ω

now with this value we can find the inductance of the coil

            τ = L / R

            L = τ  R

            L = 1.20 10⁻⁴   5.2

            L = 6.24 10⁻⁴ H

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Jack could be displaying sexism
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