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JulsSmile [24]
3 years ago
5

A telescope can be used to enlarge the diameter of a laser beam and limit diffraction spreading. The laser beam is sent through

the telescope in opposite the normal direction and can then be projected onto a satellite or the Moon. If this is done with the Hale telescope, producing a 5.08 m diameter beam of 613 nm light, what is the minimum angular spread of the beam?
Physics
1 answer:
Novay_Z [31]3 years ago
5 0

Answer:

Angular spread, \theta=1.472\times 10^{-7}\ rad

Explanation:

It is given that,

Wavelength of the light, \lambda=613\ nm=613\times 10^{-9}\ m

Diameter of the telescope, D = 5.08 m

The minimum angular spread is given by :

\theta=\dfrac{1.22\lambda}{D}

\theta=\dfrac{1.22\times 613\times 10^{-9}}{5.08}

\theta=1.472\times 10^{-7}\ rad

So, the minimum angular spread of the beam is 1.472\times 10^{-7}\ radian. Hence, this is the required solution.

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A hypothetical planet has a mass 2.81 times that of Earth, but the same radius.
patriot [66]

The acceleration due to gravity near the surface of the planet is 27.38 m/s².

<h3>Acceleration due to gravity near the surface of the planet</h3>

g = GM/R²

where;

  • G is universal gravitation constant
  • M is mass of the planet
  • R is radius of the planet
  • g is acceleration due to gravity = ?

g = (6.626 x 10⁻¹¹ x 2.81 x 5.97 x 10²⁴) / (6371 x 10³)²

g = 27.38 m/s²

Thus, the acceleration due to gravity near the surface of the planet is 27.38 m/s².

Learn more about acceleration due to gravity here: brainly.com/question/88039

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4 0
1 year ago
A 150-newton force, applied to a wooden crate at an angle of 30° above the horizontal, causesthe crate to travel at constant vel
omeli [17]

Answer:

Explanation:

A component of 150 N in vertical direction will reduce the magnitude of reaction force.

reaction force exerted by the floor

= mg - 150 sin 30

where m is mass of the crate .

the magnitude of the horizontal component of the 150-newton force

150 cos30

= 130 N

This force tries to pull the crate in forward direction with acceleration but it has no acceleration . It is so because frictional force of equal magnitude acts on it in opposite direction which makes the net force acting on it equal to zero.

Hence frictional force is equal to 150 cos 30.

= 130 N .

3 0
3 years ago
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Natalka [10]
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7 0
3 years ago
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In the Millikan oil drop experiment the measured charge of any single droplet was always a whole number multiple of -1.60 x 10-1
BaLLatris [955]

Answer:

Number of electrons, n = 6

Explanation:

Total charge in a single droplet, q=-9.6\times 10^{-19}\ C

The measured charge of any single droplet, e=-1.6\times 10^{-19}\ C

Let n is the number of excess electrons are contained within the drop. According to the quantization of charge :

q=ne

n=\dfrac{q}{e}

n=\dfrac{-9.6\times 10^{-19}}{-1.6\times 10^{-19}}

n = 6

So, there are 6 electrons contained within the drop. Hence, this is the required solution.

7 0
3 years ago
A constant force of 20. newtons applied to a box causes it to move at a constant speed of 4.0 meters per second. How much work i
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