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4 years ago

Why does the area around the equator stay about the same temperature year round?

1 answer:

3 0

Axial Tilt and Sun Energy

This axial tilt means that during the Earth's journey around the sun the poles receive varying amounts of sunlight. The equator, however, receives relatively consistent sunlight all year. The consistency of energy means the equator's temperature stays relatively constant all year.

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What is the function of the lens of an eye?

VladimirAG [237]

Answer:

to see the beautiful world

to focus the light onto the retina

4 0

3 years ago

Read 2 more answers

Which of the following expressions will have units of kg⋅m/s2? Select all that apply, where x is position, v is velocity, m is m

netineya [11]

Answer: $m \frac{d}{dt}v_{(t)}$

Explanation:

In the image attached with this answer are shown the given options from which only one is correct.

The correct expression is:

$m \frac{d}{dt}v_{(t)}$

Because, if we derive velocity $v_{t}$ with respect to time $t$ we will have acceleration $a$ , hence:

$m \frac{d}{dt}v_{(t)}=m.a$

Where $m$ is the mass with units of kilograms ( $kg$ ) and $a$ with units of meter per square seconds $\frac{m}{s}^{2}$ , having as a result $kg\frac{m}{s}^{2}$

The other expressions are incorrect, let’s prove it:

$\frac{m}{2} \frac{d}{dx}{(v_{(x)})}^{2}=\frac{m}{2} 2v_{(x)}^{2-1}=mv_{(x)}$ This result has units of $kg\frac{m}{s}$

$m\frac{d}{dt}a_{(t)}=ma_{(t)}^{1-1}=m$ This result has units of $kg$

$m\int x_{(t)} dt= m \frac{{(x_{(t)})}^{1+1}}{1+1}+C=m\frac{{(x_{(t)})}^{2}}{2}+C$ This result has units of $kgm^{2}$ and $C$ is a constant

$m\frac{d}{dt}x_{(t)}=mx_{(t)}^{1-1}=m$ This result has units of $kg$

$m\frac{d}{dt}v_{(t)}=mv_{(t)}^{1-1}=m$ This result has units of $kg$

$\frac{m}{2}\int {(v_{(t)})}^{2} dt= \frac{m}{2} \frac{{(v_{(t)})}^{2+1}}{2+1}+C=\frac{m}{6} {(v_{(t)})}^{3}+C$ This result has units of $kg \frac{m^{3}}{s^{3}}$ and $C$ is a constant

$m\int a_{(t)} dt= \frac{m {a_{(t)}}^{2}}{2}+C$ This result has units of $kg \frac{m^{2}}{s^{4}}$ and $C$ is a constant

$\frac{m}{2} \frac{d}{dt}{(v_{(x)})}^{2}=0$ because $v_{(x)}$ is a constant in this derivation respect to $t$

$m\int v_{(t)} dt= \frac{m {v_{(t)}}^{2}}{2}+C$ This result has units of $kg \frac{m^{2}}{s^{2}}$ and $C$ is a constant

6 0

3 years ago

QuestIuI

WARRIOR [948]

Given Information:

Mass of elephant = m = 750 kg

Height = h = 14.3 m

time = t = 30 seconds

Required Information:

Power needed to lift elephant = P = ?

Answer:

Power needed to lift elephant ≈ 3507 watts

Explanation:

As we know power is given by

P = PE/t

Where PE is the potential energy and t is the time

Potential energy is given by

PE = mgh

Where m is the mass of elephant, g is the gravitational acceleration and h is the height to lift the elephant.

PE = 750*9.81*14.3

PE = 105212.25 Joules

Therefore, the required power to lift the elephant is

P = PE/t

P = 105212.25/30

P ≈ 3507 watts

8 0

4 years ago

Emanuel Zacchini, the famous human cannonball of the Ringling Bros. and Barnum &

weqwewe [10]

Answer:

We have that Assuming No air resistance,the initial horizontal velocity of the cannonball is

From the question we are told that

A cannonball is shot from a cannon at a launch angle of 35 and an initial velocity of 147 m/s

Generally the equation for the horizontal velocity is mathematically given as

Therefore

Therefore Assuming No air resistance,the initial horizontal velocity of the cannonball is For more information on this visit

Explanation:

4 0

3 years ago

The charge on the square plates of a parallel-plate capacitor is Q. The potential across the plates is maintained with constant

uysha [10]

Answer:

The amount of charge on the plates is now equal to half its original value

Explanation:

From the question we are told that

The charge on the plate is Q

The initial separation is $d_1$

The new separation is $d_2 = 2 d_1$

Generally the capacitance of the capacitor is mathematically represented as

$C = \frac{\epsilon * A }{d}$

Generally the charge of the parallel plate capacitor is mathematically represented as

$Q =CV$

=> $Q =\frac{\epsilon * A * V }{ d}$

Here $\epsilon$ , A and V are constant , so looking at the question we see that Q varies inversely with d

$Q = \frac{K}{d}$

Here K is a constant

$Qd = K$

=> $Q_1 d_1 = Q_2 * d_2$

=> $Q_1 d_1 = Q_2 * [2 d_1]$

=> $Q_2 = \frac{Q_1}{2}$

So we see from the mathematically relation that the charge of the parallel plate capacitor will reduce by half of it original value

3 0

3 years ago