A student is getting ready to go on a bike ride, but her bike’s back tire is flat! She connects a pump to the valve and adds air
to the tire until it is fully inflated and ready to ride.
After the addition of air to the tire, the air pressure inside the tire is now __________ the air pressure outside the tire.
Fill in the blank by choosing one answer below.
After the addition of air to the tire, the air pressure inside the tire is now __________ the air pressure outside the tire.
Fill in the blank by choosing one answer below.
2 answers:
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Given:
mass: 100 kg
height: 500 m
1 kJ = 1000 J
gravity = 9.8 m/s²
velocity before impact: v = √2gh ; v = √2 * 9.8 m/s² * 500 m ; v = 98.99494 m/s
KE = 1/2 m v²
KE = 1/2 * 100 kg * (98.99494 m/s)²
KE = 490,000 J
Pls. see attachment.
mass: 100 kg
height: 500 m
1 kJ = 1000 J
gravity = 9.8 m/s²
velocity before impact: v = √2gh ; v = √2 * 9.8 m/s² * 500 m ; v = 98.99494 m/s
KE = 1/2 m v²
KE = 1/2 * 100 kg * (98.99494 m/s)²
KE = 490,000 J
Pls. see attachment.
Here, height is given which will be the distance for a freely falling object.
The velocity will be
and the acceleration will be
In this way, the formula works.