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2 years ago

If a factory can produce 17 cars in 1 week, how many cars will it produce in 5 weeks?

Mathematics

2 answers:

muminat2 years ago

7 0

85 cars, tip: 17 • 5

Ainat [17]2 years ago

3 0

Answer:

85cars

Step-by-step explanation:

(╯°□°）╯︵ ┻━┻(╯°□°）╯︵ ┻━┻

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The price of an item has risen to $ 299 today. Yesterday it was $130.

hoa [83]

Answer:

It has risen by $169

Step-by-step explanation:

299

130

----------

169

7 0

2 years ago

If it costs $3.50 per square foot, what is the approximate total cost of making this

Leni [432]

Answer:

the right answer would be C

7 0

2 years ago

Read 2 more answers

Pls pls help!!!!!!!!!!

netineya [11]

9514 1404 393

Answer:

Step-by-step explanation:

Let f represent the number of friends. Their total earnings are ...

21f = 105

f = 105/21 = 5 . . . . . divide by the coefficient of f

There are 5 friends in the group.

5 0

2 years ago

Find the price-demand equation for a particular brand television when the demand is 20 TVs per week at $150 per TV, given that t

Alina [70]

Answer:

~ $150=50e^{-0.01()20}$

~ $p(100)=\$127.7$

Step-by-step explanation:

From the question we are told that:

Price of 20TVs per week $P_{20}=\$150$

Marginal price-demand function $p'(x)=-0.5e-0.01x$

Generally the The Marginal price function is mathematically given by

$p'(x)=-0.5e^{-0.01x}$

$p(x)=\int-0.5e^{-0.01x}$

$p(x)=50e^{-0.001x}+C$

Therefore the equation when the demand is 20 TVs per week at $150 per TV

$150=50e^{-0.01()20}$

Giving

$p(x)=50e^{-0.01x}+150-50e^{-0.01(20)}$

Therefore the Price when the demand is 100 TVs per week

$p(100)=50e^{-0.01(100)}+150-50e^{-0.01(20)}$

$p(100)=\$127.7$

7 0

2 years ago

Solve the equation ?

Morgarella [4.7K]

6m+1=-23. Do the inverse operation of adding 1 which is to subtract 1 to both sides =====> 6m+1-1= -23-1

You divide by 6 both sides
6m/6=-24/6

m= -4

Brainliest?

3 0

3 years ago