Answer:
N = N0 e^-x t is the general form for Half-Life decay of atoms
B would be the correct choice
<h2>
Answer:</h2><h2>n=-5</h2>
n
-
4
=
3
+
6
n-4=3n+6
n−4=3n+6
Solve
1
Add
4
4
4
to both sides of the equation
−
4
=
3
+
6
n-4=3n+6
n−4=3n+6
−
4
+
4
=
3
+
6
+
4
n-4+{\color{#c92786}{4}}=3n+6+{\color{#c92786}{4}}
n−4+4=3n+6+4
2
Simplify
3
Subtract
3
3n
3n
from both sides of the equation
4
Simplify
5
Divide both sides of the equation by the same term
6
Simplify
Answer:
True?
Step-by-step explanation:
I think its true but I'm not 100% sure so I would go with true. Try thinking of your past problems that you used and think about that maybe? But in then mean time, I would go with True
Answer:
a n = -3+(n-1)-30
Step-by-step explanation:
-3 - 30 = -33
-33 - 30 = -63
-63 - 30 = -93
The common difference here is -30. d = -30
The explicit formula is a n = a1 + (n-1)d
Answer:
Step-by-step explanation:
Total number of antenna is 15
Defective antenna is 3
The functional antenna is 15-3=12.
Now, if no two defectives are to be consecutive, then the spaces between the functional antennas must each contain at most one defective antenna.
So,
We line up the 13 good ones, and see where the bad one will fits in
__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __
Each of the places where there's a line is an available spot for one (and no more than one!) bad antenna.
Then,
There are 14 spot available for the defective and there are 3 defective, so the arrange will be combinational arrangement
ⁿCr= n!/(n-r)!r!
The number of arrangement is
14C3=14!/(14-3)!3!
14C3=14×13×12×11!/11!×3×2
14C3=14×13×12/6
14C3=364ways
