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Afina-wow [57]
3 years ago
12

Which type of wave forms at the boundary between air and water when you

Physics
2 answers:
ivann1987 [24]3 years ago
7 0
Answer:
D. Transverse
Explanation:
If you throw a rock into a pond ripples spread out from where it went in.These ripples are waves travelling through the water. The waves move with a transverse motion. The undulations are at 90 degrees to the direction of travel .
azamat3 years ago
6 0

D. Transverse wave

Hope it's correct and helps uh.

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Lucia is playing with magnetic toy vehicles. She has two identical toy vehicles (purple and pink) that start on opposite sides o
jekas [21]

Answer: The potential energy of both toy vehicles (purple and pink) decreased. Since the pink toy was moved closer to the magnet, it will have less potential energy because of the short distance it will take to travel to the magnet.

Explanation:

Brainliest

3 0
3 years ago
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The concrete sections of a certain superhighway are designed to have a length of 23.0 m. The sections are poured and cured at 10
loris [4]

Answer:

0.88 cm

Explanation:

Initial length at 10°c, L = 23 m

Rise of temperature, Δt = 42 - 10 = 32°c

Coefficient of linear expansion of concrete, α = 12 x 10^(-6) per°c

Minimum spacing to be left = α L Δt

=12\times10^{-6}\times23\times32

=8.832\times10^{-3}m

= 8.832 x 10^{-1} cm

= 0.88 cm

Note: I have a chosen a general value of 12 x 10^-6 per deg c for coefficient of expansion of  concrete. However, please refer to the value given in your text book and substitute it for an accurate answer.

8 0
3 years ago
What is the name of the device that measures wind speed?
myrzilka [38]
The device is an anemometer<span> 
It's like 4 cups that measure the speed instead of direction

</span>
8 0
4 years ago
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Consider the circuit shown in the figure to find the power delivered to 6 Ohm resistance (in W). Given that Vs= 30
vekshin1

66.7 Watts

Explanation:

Let R_{1}=1.0 ohms, R_{2}=3.0ohms and R_{3}=6.0\:ohms. Since R_{2} and R_{3} are in parallel, their combined resistance R_{23} is given by

\dfrac{1}{R_{23}}=\dfrac{1}{R_{2}}+\dfrac{1}{R_{3}}

or

R_{23}=\dfrac{R_{2}R_{3}}{R_{2}+ R_{3}}=2.0\:ohms

The total current flowing through the circuit <em>I</em> is given

I=\dfrac{V_{s}}{R_{Total}}

where

R_{Total}=R_{1}+R_{23}= 3.0\:ohms

Therefore, the total current through the circuit is

I=\dfrac{30\:V}{3.0\:ohms}=10\:A

In order to find the voltage drop across the 6-ohm resistor, we first need to find the voltage drop across the 1-ohm resistor V_{1}:

V_{1}=(10\:A)(1.0\:ohms)=10\:V

This means that voltage drop across the 6-ohm resistor V_{3} is 20 V. The power dissipated <em>P</em> by the 6-ohm resitor is given by

P=I^{2}R_{3}= \dfrac{V^{2}}{R_{3}}=\dfrac{(20\:V)^{2}}{6\:ohms}= 66.7 W

4 0
3 years ago
I need help with this answer
ololo11 [35]
The answer is Synthesis
7 0
3 years ago
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