Answer:
The valve should be closed at 1081 kPa ⇒ 11 bar
Explanation:
![m_2 = \frac{[10.994*1509.9] + [4.006*1057.5]}{15} = 1389.1 kJ/kg](https://tex.z-dn.net/?f=m_2%20%3D%20%5Cfrac%7B%5B10.994%2A1509.9%5D%20%2B%20%5B4.006%2A1057.5%5D%7D%7B15%7D%20%20%3D%201389.1%20kJ%2Fkg)
Therefore, v₂, u₂ fix state 2.
By trial and error, P₂ = 1081 kPa & T₂ = 50.4° C
1081 kPa ⇒ 11 bar
Answer:
pls mark me as brainliest
Explanation:
Answer: 7.36 mA
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Answer:
Denser and more viscous crude oils have greater concentrations of other components, including resins and asphaltenes, which contain more polar compounds, often including “heteroatoms” of nitrogen, sulfur, and oxygen as well as carbon and hydrogen.
Answer:I am so sorry but here are no questions, thanks for the points
Explanation:Have a nice day
