Answer:
Net efficiency of generating unit = 42.08 - 5 = 37.08 %
Explanation:
We have given that efficiency of the boiler = 91.2 % = 0.912
Carnot efficiency = 46.9 % = 0.469
Efficiency of generator = 98.4% =0.984
We have to find the efficiency of total generating unit
For finding the efficiency of total generating unit we have to multiply all the efficiencies
So efficiency of generating unit = 0.912×0.469×0.984 = 0.4208 = 42.08 %
For plant losses we have to subtract 5%
So net efficiency of generating unit = 42.08 - 5 = 37.08 %
Answer:
M_c = 61.6 Nm
Explanation:
Given:
F_a = 2.5 KN
Find:
Determine the moment of this force about C for the two casesshown.
Solution:
- Draw horizontal and vertical vectors at point A.
- Take moments about point C as follows:
M_c = F_a*( 42 / 150 ) *88
M_c = 2.5*( 42 / 150 ) *88
M_c = 61.6 Nm
- We see that the vertical component of force at point A passes through C.
Hence, its moment about C is zero.
Answer:
Class of fit:
Interference (Medium Drive Force Fits constitute a special type of Interference Fits and these are the tightest fits where accuracy is important).
Here minimum shaft diameter will be greater than the maximum hole diameter.
Medium Drive Force Fits are FN 2 Fits.
As per standard ANSI B4.1 :
Desired Tolerance: FN 2
Tolerance TZone: H7S6
Max Shaft Diameter: 3.0029
Min Shaft Diameter: 3.0022
Max Hole Diameter:3.0012
Min Hole Diameter: 3.0000
Max Interference: 0.0029
Min Interference: 0.0010
Stress in the shaft and sleeve can be considered as the compressive stress which can be determined using load/interference area.
Design is acceptable If compressive stress induced due to selected dimensions and load is less than compressive strength of the material.
Explanation:
Umm the Water cycle sorry I’m trying