Ask question

Ask question

All categories

2 years ago

11

A motor car shaft consists of a steel tube 30 mm internal diameter and 4 mm thick. The engine develops 10 kW at 2000 r.p.m. Find

the maximum shear stress in the tube when the power is transmitted through a 4: 1 gearing.

1 answer:

tresset_1 [31]2 years ago

7 0

The maximum shear stress in the tube when the power is transmitted through a 4: 1 gearing is 28.98 MPa.

<h3>What is power?</h3>

Power is the energy transferred per unit time.

Torque is find out by

P = 2πNT/60

10000 = 2π x 2000 x T / 60

T =47.74 N.m

The gear ratio Ne / Ns =4/1

Ns =2000/4 = 500

Ts =Ps x 60/(2π x 500)

Ts =190.96 N.m

Maximum shear stress τ = 16/π x (T / (d₀⁴ - d₁⁴))

τ max =T/J x D/2
where d₁ = 30mm = 0.03 m

d₀ = 30 +(2x 4) = 38mm =0.038 m

Substitute the values into the equation, we get

τ max = 16 x 190.96 x 0.038 /π x (0.038⁴ - 0.03⁴)

τ max = 28.98 MPa.

Thus, the maximum shear stress in the tube is 28.98 MPa.

Learn more about power.

brainly.com/question/13385520

#SPJ1

You might be interested in

An FCC iron-carbon alloy initially containing 0.20 wt% C is carburized at an elevated temperature and in an atmosphere wherein t

weeeeeb [17]

Answer:

the temperature T at which the treatment is carried is out is 1274.24 K

Explanation:

Fick's second Law posits that the rate of change of concentration of diffusing species is directly proportional to the second derivative of the concentration.

Using the expression of the Fick's second Law:

$\mathbf{\frac{C_x-C_o}{C_s-C_o} = 1- erf(\frac{x}{2\sqrt{Dt} })}$

where;

$C_o$ = initial concentration

$C_x$ = the depth of the concentration

$C_s$ = surface concentration

$erf(\frac{x}{2\sqrt{Dt} })}$ = Gaussian error function.

Let variable z be used for the expression of the Gaussian error function. $erf(\frac{x}{2\sqrt{Dt} })}$

Then, from the above equation: replacing $C_x$ with 0.35 ; $C_o$ with 0.2 and $C_s$ with 1.0; we have:

$\mathbf{\frac{0.35-0.2}{1.0-0.2} = 1- erf( z)}$

erf (z) = 0.8125

we obtain the error function value close to 0.8125 from the error function table and we did the interpolation to obtain the exact value of variable corresponding to 0.8125.

The table below shows the tabular form of the error function value close to 0.8125 .

Value for z Value for erf (z)

0.9 0.797

z 0.8125

0.950 0.8209

From above; we can find the value of variable corresponding to the error function 0.8125 .

i.e

$\frac{z-0.9}{0.95-0.9} =\frac{0.8125-0.797}{0.8209-0.797}$

z = 0.932

However, the temperature dependence relation for the diffusion coefficient D can be expressed as:

$z = \frac{x}{\sqrt{Dt} }$

where;

z = 0.932

x = 3.5 mm = 0.0035 m

t = 50 h = 180000 sec

$0.932 = \frac{0.35}{2\sqrt{D*180000} }$

D = $1.958*10^{-11} m^2/s$

Finally, the temperature T at which the treatment is carried is out is calculated as:

$\mathbf{D=D_o \ exp \ (-\frac{Q_d}{RT}) }$

From the table ‘Diffusion data’, we obtain the values of temperature-independent pre exponential and activation energy for diffusion of carbon in FCC Fe.

$D_o = 2.3*10^{-5} \ m^2/s$

$Q_d = 148, 000 \ J/mol$

Replacing all values needed for the above equation; we have:

$1.958*10^{-11}= (2.3*10^{-5})exp(\frac{-148,000}{(8.31)T})$

$8.51*10^{-7}=exp(\frac{-17,810}{T})$

$In(8.51*10^{-7})=(\frac{-17,810}{T})$

-13.977 = -17,810/T

T = -17,810/ - 13.977

T = 1274.24 K

Hence, the temperature T at which the treatment is carried is out is 1274.24 K

5 0

3 years ago

Give five examples of

olchik [2.2K]

Answer:

to reduce the amount paid to suppliers. For example, a retailer with great buying power (Walmart, Amazon) can offer very small profit margins to suppliers as they have little alternative.Collusion between existing firms in an industry to exclude new firms from deals to prevent the market from becoming more competitive.Sticking to output quotas and higher prices.Collusive tendering. For example, ‘cover prices’ for competitive tendering in bidding for public construction contracts. This is when a rival firm agrees to set artificially high price to allow the firm of choice to win with a relatively high contract offer.Types of collusionFormal collusion – when firms make formal agreement to stick to high prices. This can involve the creation of a cartel. The most famous cartel is OPEC – an organisation concerned with setting prices for oil.Tacit collusion – where firms make informal agreements or collude without actually speaking to their rivals. This may be to avoid detection by government regulatorsPrice leadership. It is possible firms may try to unofficially collude by following the prices set by a market leader. This enables them to keep prices high, without ever meeting with rival firms. This kind of collusion is hard to prove whether it is unfair competition or just the natural operation of markets.Problems of collusionCollusion is seen as bad for consumers and economic welfare, and therefore collusion is mostly regulated by governments. Collusion can lead to:High prices for consumers. This leads to a decline in consumer surplus and allocative inefficiency (Price pushed up above marginal cost)New firms can be discouraged from entering the market by types of collusion which act as a barrier to entry.Easy profits from collusion can make firms lazy and avoid innovation and efforts to increase productivity.Industry gets the disadvantages of monopoly (higher price) but none of the advantages (e.g. economies of scale)Justification for collusionIn times of unprofitable business conditions, collusion may be a way to try and save the industry and prevent firms from going out of business, which wouldn’t be in the long-term consumer interest. Dairy suppliers tried to use this justification in 2002/03 after problems from foot and mouth disease led to a decline in farm incomes.Research and development. Profits from collusion could, in theory, be used to invest in research and development.Milk price by supermarkets 2002-03After a period of low milk, butter and cheese

3 0

2 years ago

Can I put a fork in electric socket?

erastova [34]

Answer:

don't put fork in a electric socket

4 0

3 years ago

Read 2 more answers

Fuel filters are being replaced on a HPCR diesel

saw5 [17]

Answer:) The correct answer is B. at the end of the fuel rail.

2) The one who is correct is the Technician A.

Explanation:

7 0

3 years ago

. Using the Newton Raphson method, determine the uniform flow depth in a trapezoidal channel with a bottom width of 3.0 m and si

Over [174]

Answer:

y ≈ 2.5

Explanation:

Given data:

bottom width is 3 m

side slope is 1:2

discharge is 10 m^3/s

slope is 0.004

manning roughness coefficient is 0.015

manning equation is written as

$v =1/n R^{2/3} s^{1/2}$

where R is hydraulic radius

S = bed slope

$Q = Av =A 1/n R^{2/3} s^{1/2}$

$A = 1/2 \times (B+B+4y) \times y =(B+2y) y$

$R =\frac{A}{P}$

P is perimeter $= (B+2\sqrt{5} y)$

$R =\frac{(3+2y) y}{(3+2\sqrt{5} y)}$

$Q = (2+2y) y) \times 1/0.015 [\frac{(3+2y) y}{(3+2\sqrt{5} y)}]^{2/3} 0.004^{1/2}$

solving for y $100 =(2+2y) y) \times (1/0.015) [\frac{(3+2y) y}{(3+2\sqrt{5} y)}]^{2/3} \times 0.004^{1/2}$

solving for y value by using iteration method ,we get

y ≈ 2.5

5 0

3 years ago