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ivann1987 [24]
3 years ago
10

You are given the following information about a drybatch paving operation. You are going to use one mixer that has a service rat

e of 30 services per hour. The dry-batch trucks you use for bringing concrete to the paver have an arrival rate of 7.5 arrivals per hour. Each truck carries 6 cubic yard of concrete. You have a total amount of 13,500 cubic yard of concrete to pour. You rent a truck at $15 per hour and the paver at $60 per hour. If the job takes more than 80 hours, you pay a penalty of $140 perhour owing todelays injob completion. Onthe basis of least cost, determine the number of trucks you should use. Plot the cost versus the number of trucks used.

Engineering
1 answer:
umka21 [38]3 years ago
5 0

Answer:

Answer for the question:

You are given the following information about a drybatch paving operation. You are going to use one mixer that has a service rate of 30 services per hour. The dry-batch trucks you use for bringing concrete to the paver have an arrival rate of 7.5 arrivals per hour. Each truck carries 6 cubic yard of concrete. You have a total amount of 13,500 cubic yard of concrete to pour. You rent a truck at $15 per hour and the paver at $60 per hour. If the job takes more than 80 hours, you pay a penalty of $140 perhour owing todelays injob completion. Onthe basis of least cost, determine the number of trucks you should use. Plot the cost versus the number of trucks used.

is given in the attachment.

Explanation:

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The rate at which velocity changes is called acceleration

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A 300 mm long steel bar with a square cross section (25 mm per edge) is pulled in tension with a load of 83,051 N , and experien
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the answer is attached with required units.

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3 years ago
Which of these processes uses a die and a press to form parts?
Irina-Kira [14]

The process of die forming that uses a die and a press to form parts from the given processes is called; C: Hydroforming

<h3>What are some of the steps in the die forming operations?</h3>

There are different types of die forming in sheet metal operations. Now, Hydroforming is a specialized type of die forming that uses a high pressure hydraulic fluid to press room temperature working material into a die.

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2 years ago
1)What are the three previous manufacturing revolutions Mr. Scalabre mentions? When did these take place?
Ostrovityanka [42]

The three previous manufacturing revolutions that Mr. Scalabre mentioned and their year of occurrence are:

  1. The steam engine in the mid-19th Century
  2. The mass-production model in the early 20th Century
  3. The first automation wave in the 1970s

<h3>What is a Manufacturing Revolution?</h3>

This refers to the process of change from a handicraft economy to industry production-based production.

Hence, we can see that Mr. Scalabre believes we are not growing in productivity because there has not been enough automation to perform the tasks needed.

The effect of robotics is making an impact on productivity because a lot of complex, difficult tasks are done by machines.

3D printing has made an impact on productivity because there is a reduction in the pressing cycle and errors due to negligence are reduced.

The role the engineers have to play in the next revolution is that they would have to produce mathematical model that can be used to produce better AIs

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8 0
2 years ago
A satellite orbits the Earth every 2 hours at an average distance from the Earth's centre of 8000km. (i) What is the average ang
AlexFokin [52]

Answer:

i)ω=3600 rad/s

ii)V=7059.44 m/s

iii)F=1245.8 N

Explanation:

i)

We know that angular speed given as

\omega =\dfrac{d\theta}{dt}

We know that for one revolution

θ=2π

Given that time t= 2 hr

So

ω=θ/t

ω=2π/2 = π rad/hr

ω=3600 rad/s

ii)

Average speed V

V=\sqrt{\dfrac{GM}{R}}

Where M is the mass of earth.

R is the distance

G is the constant.

Now by putting the values

V=\sqrt{\dfrac{GM}{R}}

V=\sqrt{\dfrac{6.667\times 10^{-11}\times 5.98\times 10^{24}}{8000\times 10^3}}

V=7059.44 m/s

iii)

We know that centripetal fore given as

F=\dfrac{mV^2}{R}

Here given that m= 200 kg

R= 8000 km

so now by putting the values

F=\dfrac{mV^2}{R}

F=\dfrac{200\times 7059.44^2}{8000\times 10^3}

F=1245.8 N

3 0
3 years ago
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