Answer:
The inventor's claim is false in the sense that no thermal machine can violate the first thermodynamic law.
Explanation:
The inventor's claim could not be possible as no thermal machine can transfer more heat than the input work consumed. If we expose the thermal efficiency:
Where Q and W both must be in the same power unit, so we will convert the remove heat from BTU/hr to hp:
Therefore by comparing, we notice that the removing heat of 4.75 hp is large than the delivered work of 1.11 hp. By evaluating the efficiency:
[tex]n=4.75 hp / 1.1 hp = 4.3 > 1[/tex]
Answer:
a. True - Because the atomic arrangements of that region is disorderer because of the extra half plane atoms in between the line
b.Slip
C. Strength theoretical is greater than strength experimental
d. Shear stress
e. Highest linear density
Answer:
ηa=0.349
ηb=0.345
Explanation:
The enthalpy and entropy at state 3 are determined from the given pressure and temperature with data from table:
The quality at state 4 is determined from the condition 
and the entropies of the components at the condenser pressure taken from table:
The enthalpy at state 4 then is:
Part A
In the case when the water is in a saturated liquid state at the entrance of the pump the enthalpy and specific volume are determined from A-5 for the given pressure:
The enthalpy at state 2 is determined from an energy balance on the pump:
=346.67 kJ/kg
The thermal efficiency is then determined from the heat input and output in the cycle:
Part B
In the case when the water is at a lower temperature than the saturation temperature at the condenser pressure we look into table and see the water is in a compressed liquid state. Then we take the enthalpy and specific volume for that temperature with data from and the saturated liquid values:
The enthalpy at state 2 is then determined from an energy balance on the pump:
=299.79 kJ/kg
The thermal efficiency in this case then is:
Answer:
diameter is 14.83 mm
Explanation:
given data
height = 2 mm
to find out
internal diameter
solution
we consider here material is glass and liquid is water and angle is zero if no capillary rise
we apply here capillary rise formula that is
Capillary rise h = 2T / [ r×ρ×g ] ....................1
put here r is radius and ρ = 1000 kg/m³, T = 72.7 ×
N/m all value in equation 1
Capillary rise h = 2T / [ r×ρ×g ]
r = 2T / [ h×ρ×g ]
d/2 = 2T / [ h×ρ×g ]
d/2 = 2( 72.7 ×) / [ 2××1000×9.8 ]
d = 0.0148336 m
so diameter is 14.83 mm
