Answer:
im leaning on parallelogram
Step-by-step explanation:
N(2n+6)-(n²-1)= 2n²+6n-n²+1=n²+6n+1
Cost of each pound of dog food = $2 .
Total cost of 9 pounds of dog food = 9 * 2 = $18.
Let us assume number of treats she can buy = t.
Cost of each treat = $1.
Cost of t number of treats = 1*t = 1t .
Total money Cara has = $25.
We can setup an inequality as,
Total cost of dog food + total cost of t number of treats ≤ 25.
18 + 1t ≤ 25.
Subtracting 18 from both sides, we get
18 + 1t -18 ≤ 25-18.
1t ≤ 7 or t ≤ 7.
So, she can purchase 7 or less treats.
Answer:
- (6-u)/(2+u)
- 8/(u+2) -1
- -u/(u+2) +6/(u+2)
Step-by-step explanation:
There are a few ways you can write the equivalent of this.
1) Distribute the minus sign. The starting numerator is -(u-6). After you distribute the minus sign, you get -u+6. You can leave it like that, so that your equivalent form is ...
(-u+6)/(u+2)
Or, you can rearrange the terms so the leading coefficient is positive:
(6 -u)/(u +2)
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2) You can perform the division and express the result as a quotient and a remainder. Once again, you can choose to make the leading coefficient positive or not.
-(u -6)/(u +2) = (-(u +2)-8)/(u +2) = -(u+2)/(u+2) +8/(u+2) = -1 + 8/(u+2)
or
8/(u+2) -1
Of course, anywhere along the chain of equal signs the expressions are equivalent.
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3) You can separate the numerator terms, expressing each over the denominator:
(-u +6)/(u+2) = -u/(u+2) +6/(u+2)
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4) You can also multiply numerator and denominator by some constant, say 3:
-(3u -18)/(3u +6)
You could do the same thing with a variable, as long as you restrict the variable to be non-zero. Or, you could use a non-zero expression, such as 1+x^2:
(1+x^2)(6 -u)/((1+x^2)(u+2))
