Answer:
0.79 cm
Explanation:
The computation is shown below:-
Particle acceleration is
We will take d which indicates distance as from the negative plate, so the travel by proton is 0.800 cm - d at the same time
After solving the equation we will get 0.79 cm from the negative plate.
Therefore it is 0.79 cm far from the negative pate i.e the point at which the electron and proton pass each other
Answer: Got it!
Explanation: The water in a river flows uniformly at a constant speed of 2.50m/s between two parallel banks 80.0m apart. You are to deliver a package directly across the river, but you can only swim at 1.5m/s.
We have that the time, to the nearest minute, when the water level is at 1.125 m for the second time after midnight is
From the Question we are told that
Maximum height
Minimum height
Time for next high tide will occur
Generally Average Height
Therefore determine Amplitude to be
Generally, the equation for Time is mathematically given by
At t=0
Where
Therefore
Hence the Time at is
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<span>Coefficient of static friction needs to be 1.1 or larger.
For this problem, we need to static friction to be at least as large as the centripetal acceleration that the car will experience. So let's get our formulas.
Centripetal acceleration:
F = mv^2/r
where
F = force
m = mass
v = velocity
r = radius of curve
Friction
F = mac
where
F = force
m = mass
a = gravitational acceleration
c = coefficient of friction
Since the frictional force has to be at least as large as the Centripetal force, let's set an inequality between them.
mv^2/r ≤ mac
v^2/r ≤ ac
v^2/(ar) ≤ c
Now let's convert km/h to a more convenient m/s.
104 km/h / 3600 s/h * 1000 m/km = 28.88888889 m/s
Let's substitute the known values into the inequality and calculate.
v^2/(ar) ≤ c
(28.88888889 m/s)^2/(9.8 m/s^2 * 78 m) ≤ c
834.5679012 m^2/s^2 / 764.4 m^2/s^2 ≤ c
1.091794743 ≤ c
Rounded to 2 significant figures gives a required coefficient of static friction of 1.1 or greater. This is a rather large value and indicates that the car is not at all likely to be capable of taking that curve at that speed. There are some things that can be done to mitigate the issue. Those being
1. Reduce the velocity.
2. Increase the normal force. Perhaps by aerodynamic means
3. Bank the curve.</span>