A. Every month Population will increase by a factor of 0.84%.
B. Every 3 months Population will increase by a factor of 2.5%.
C. Increase in population in every 20 months is 10% + 6.72% = 16.72%.
<u>Step-by-step explanation:</u>
Here, we have number of employees in a company has been growing exponentially by 10% each year. So , If we have population as x in year 2019 , an increase of 10% in population in 2020 as
which is equivalent to
.
<u>A.</u>
For each month: We have 12 months in a year and so, distributing 10% in 12 months would be like
. ∴ Every month Population will increase by a factor of 0.84%.
<u>B.</u>
In every 3 months: We have , 12 months in a year , in order to check for every 3 months
and Now, Population increase in every 3 months is
. ∴ Every 3 months Population will increase by a factor of 2.5%.
<u>C.</u>
In every 20 months: We have , 12 months in a year in which increase in population is 10% . Left number of moths for which we have to calculate factor of increase in population is 20-12 = 8. For 1 month , there is 0.84% increase in population ∴ For 8 months , 8 × 0.84 = 6.72 %.
So , increase in population in every 20 months is 10% + 6.72% = 16.72%.
You can set up two equations from the information given. I will set them up for you:
32 = 4x + 2y
36 = 5x + 2y
Let's solve the first equation to come up with a value for y.
32 = 4x + 2y
32 - 4x = 2y
16 - 2x = y
Now we plug y into the other equation.
36 = 5x + 2(16-2x)
36 = 5x + 32 - 4x
4 = x
Now we have our real x value and we can plug it into the first equation.
32 = 4(4) + 2y
32 = 16 + 2y
16 = 2y
8 = y
Since x = 4 and y = 8, you get the final coordinates of (4,8).
Your answer is the second statement provided above.
Answer:
200. 200 200 200 200 200 is the answer
Answer:
x=5
Step-by-step explanation:
Step 1: Subtract 3x from both sides.
6x−3−3x=3x+12−3x
3x−3=12
Step 2: Add 3 to both sides.
3x−3+3=12+3
3x=15
Step 3: Divide both sides by 3.
3x/3=15
x=5
Answer:
The standard deviation of the sampling distribution of the sample wait times is of 0.8 minutes.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30. Otherwise, the mean and the standard deviations holds, but the distribution will not be approximately normal.
Standard deviation 4 minutes.
This means that 
A sample of 25 wait times is randomly selected.
This means that 
What is the standard deviation of the sampling distribution of the sample wait times?

The standard deviation of the sampling distribution of the sample wait times is of 0.8 minutes.