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givi [52]
3 years ago
10

A force of 50 N begins to move a block of wood weighing 100 N on a

Physics
1 answer:
irga5000 [103]3 years ago
6 0

Answer:

0.5

Explanation:

From the question given above, the following data were obtained:

Force (F) = 50 N

Weight (W) = 100 N

Coefficient of static friction (μ) =.?

The coefficients of static friction (μ) is simply defined as the ratio of force (F) to the normal reaction (N). Mathematically, it can be expressed as:

μ = F / N

With the above formula, we can obtain the coefficient of static friction as follow:

Force (F) = 50 N

Weight (W) = 100 N

Coefficient of static friction (μ) =.?

μ = F / W

μ = 50 / 100

μ = 0.5

Thus, coefficient of static friction is 0.5

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(b) Find Δy when vᵧ = 0 m/s.

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0 = t (18.0 − 4.9 t)

t = 3.67

Next, find Δx when t = 3.67 s.

Δx = v₀ₓ t + ½ aₓ t²

Δx = (19 cos 71° m/s) (3.67 s) + ½ (0 m/s²) (3.67 s)²

Δx = 22.7 m

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