Answer:
The graph with a more steeper slope
Explanation:
If the x axis represented time and the y axis represented speed the steeper the slope the more faster something was moving in a shorter amount of time. On the other hand a less steeper slope means an object is gradually picking up speed in a longer amount of time thus makeing it slower
HOPE THIS HELPED:)
Answer:
A concave mirror has a radius of curvature of 20 cm. What is it's focal length? If an object is placed 15 cm in front of it, where would the image be formed? What is it's magnification?
The focal length is of 10 cm, object distance is 30 cm and magnification is -2.
Explanation:
Given:
A concave mirror:
Radius of curvature of the mirror, as C = 20 cm
Object distance in-front of the mirror = 15 cm
a.
Focal length:
Focal length is half of the radius of curvature.
Focal length of the mirror =
= 10 cm
According to the sign convention we will put the mirror on (0,0) point, of the Cartesian coordinate open towards the negative x-axis.
Object and the focal length are also on the negative x-axis where focal length and image distance will be negative numerically.
b.
We have to find the object distance:
Formula to be use:
⇒ 
⇒ Plugging the values.
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Image will be formed towards negative x-axis 30 cm away from the pole.
c.
Magnification (m) is the negative ratio of mage distance and object distance:
⇒ 
⇒ 
⇒ 
The focal length of the concave mirror, is of 10 cm, object distance is 30 cm and magnification is -2.
Answer:
It pushes food through the GI tract. The inside of GI tract is lined with mucous membranes. Mucous membranes are moist tissues that can secrete and absorb substances. The ability to secrete and absorb substances is necessary for the functions of the digestive system.
Explanation:
Can I have brainliest?
<span>The force that an object feels in an electric field is the magnitude of the electric field E times the charge on the object Q.
We know that the magnitude of the charge of an electron is 1.6 x 10^{-19} C
F = E x Q
E = F / Q
E = (3.5 x 10^{-16} N) / (1.6 x 10^{-19} C)
E = 2.19 x 10^3 N/C
The magnitude of the electric field at the location of the electron is 2.19 x 10^3 N/C</span>
Answer:
I believe the answer is D on E2020. Hope this helps