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1 year ago

How much heat is given off when 210.0g of water at 0 degrees freezes into ice?

1 answer:

5 0

In the freezing physical change, when 210.0 g of water a 0 degrees freezes into ice, it gives off 71.0 kJ of heat.

<h3>What is freezing?</h3>

It is a physical change in which liquids give off heat to form solids.

We have 210.0 g of water at 0°C. We can calculate the amount of heat given off when it freezes into ice using the following expression.

Q = ΔH°fus × m

Q = 0.334 kJ/g × 210.0 g = 70.1 kJ

where,

Q is the heat released.
ΔH°fus is the latent heat of fusion.
m is the mass.

In the freezing physical change, when 210.0 g of water a 0 degrees freezes into ice, it gives off 71.0 kJ of heat.

Learn more about freezing here: brainly.com/question/40140

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An electric motor is rated at 900 W. How much force does it apply when moving

brilliants [131]

<h3>Answer: 7.74 newtons</h3>

========================================

Steps Shown:

Work = Force*Displacement

Power = Work/Time

Power = (Force*Displacement)/Time

900 W = (F*1000 m)/(8.6 sec)

900 = (F*1000)/8.6

900*8.6 = 1000F

7740 = 1000F

1000F = 7740

F = 7740/1000

F = 7.74 newtons

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1 year ago

Which type of intelligence (analytic, creative, practical, verbal, mathematical, spatial, bodily-kinesthetic, musical, interpers

IrinaK [193]

Answer:

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Explanation:

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Intrapersonal intelligence is also reflected by Professor Wooddro as we are told he "enjoys struggling with life's most challenging questions", <u>which shows his knowledge of his own strengths or weaknesses.</u>

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2 years ago

How is it possible for the same object to have different amounts of gravitational potential energy?

Arlecino [84]

Answer:

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2 years ago

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Sauron [17]

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2 years ago

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A slingshot is used to launch a stone horizontally from the top of a 20.0 meter cliff. The stone lands 36.0 meters away.

alisha [4.7K]

A)

It is a launch oblique, therefore the initial velocity in the vertical direction is zero. Space Hourly Equation in vertical, we have:

$S=S_{o}+v_{o}t+ \frac{at^2}{2} \\ 20= \frac{10t^2}{2} \\ t=2s$

Through Definition of Velocity, comes:

$\Delta v= \frac{\Delta S}{\Delta t} \\ v_x= \frac{36}{2} \\ \boxed {v_{x}=18m/s}$

B)

Using the Velocity Hourly Equation in vertical direction, we have:

$v_{y}=v_{y_{o}}+gt \\ v_{y}=10\times2 \\ \boxed {v_{y}=20m/s}$

The angle of impact is given by:

$cos(\theta) =\frac{v_{x}}{v_{y}} \\ cos(\theta) = \frac{18}{20} \\ cos(\theta) =0.9 \\ arccos(0.9)=\theta \\ \boxed {\theta \approx 25.84}$

If you notice any mistake in my english, please let me know, because i am not native.

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2 years ago

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