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2 years ago

How much heat is given off when 210.0g of water at 0 degrees freezes into ice?

1 answer:

5 0

In the freezing physical change, when 210.0 g of water a 0 degrees freezes into ice, it gives off 71.0 kJ of heat.

<h3>What is freezing?</h3>

It is a physical change in which liquids give off heat to form solids.

We have 210.0 g of water at 0°C. We can calculate the amount of heat given off when it freezes into ice using the following expression.

Q = ΔH°fus × m

Q = 0.334 kJ/g × 210.0 g = 70.1 kJ

where,

Q is the heat released.
ΔH°fus is the latent heat of fusion.
m is the mass.

In the freezing physical change, when 210.0 g of water a 0 degrees freezes into ice, it gives off 71.0 kJ of heat.

Learn more about freezing here: brainly.com/question/40140

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3 years ago

Three Carnot engines operate between the following temperature limits.

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Explanation:

Given

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$\eta _{engine}=\frac{work\ supplied}{heat\ supplied}$

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$W_a=\frac{Q}{5}$

For b)500 K and 600K

$1-\frac{500}{600}=\frac{W_b}{Q}$

$W-b=\frac{Q}{6}$

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3 years ago

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Answer:

shadow length 7.67 cm

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by snell's law we have

$n_{air} sin30 =n_{water} sin\theta$

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solving for $\theta$

$sin\theta = \frac{3}{8}$

$\theta = sin^{-1}\frac{3}{8}$

$\theta = 22 degree$

from shadow- stick traingle

$tan(90-\theta) = cot\theta = \frac{h}{s}$

$s = \frac{h}{cot\theta} = h tan\theta$

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3 years ago

A bag is dropped from a hovering helicopter. After 42.4s, calculate the bag’s displacement.

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Answer:

8,809.024m

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y = (9.8 (42.4*42.4)) / 2

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3 years ago