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Ganezh [65]
3 years ago
15

Which of the following statement is false

Physics
2 answers:
guajiro [1.7K]3 years ago
8 0
There is nothing to choose from
Nesterboy [21]3 years ago
7 0
There is not options.
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Two soccer players kick the same 2-kg ball at the same time in opposite directions one kicks with a force of 15 n the other kick
Illusion [34]
Because the direction of the kicks are opposite, the net force between the applied forces is their difference.
                        Fn = F₂ - F₁
Substituting,
                        Fn = 15 N - 5 N
                        Fn = 10 N

From Newton's second law of motion,
                       Fn = m x a
where m is mass and a is acceleration. Manipulating the equation so that we are able to calculate for a,
                       a = Fn / m

Substituting,
                      a = (10 N) / 2 kg
                       a = 5 m/s²

<em>ANSWER: 5 m/s²</em>
7 0
3 years ago
Read 2 more answers
Why is the path of totality of a total solar eclipse on Earth so narrow?
astraxan [27]
Because it just it dndbsnsnsbsnsnsnsnsnsnsnsnsn
3 0
2 years ago
Read 2 more answers
A car travels the same distance at constant speed around two curves, one with twice the radius of curvature of the other. For wh
dexar [7]

Answer:

The answer is below

Explanation:

Centripetal acceleration is the acceleration due to the movement of an object in a uniform circular motion. The acceleration is directed towards the center of the circle.

Centripetal acceleration is given by the formula:

a = v² / r; where v is the speed of the object and r is the radius of curvature (distance from object ot the center of circle).

Let us assume the car has a velocity of v m/s. For the curve with radius of curvature r:

a₁ = v² / r

For the curve with radius of curvature r = 2r:

a₂ = v² / 2r = (1/2)a₁

Therefore the centripetal acceleration is greater in the curve with radius pf curvature r and smaller in the curve with twice the radius of curvature of the other.

6 0
3 years ago
Please help. Lol it’s easy
Oxana [17]

Answer: 100 N

Explanation:

F = ma = 0.5(200) = 100 N

8 0
2 years ago
When an airplane is flying 200 mph at 5000-ft altitude in a standard atmosphere, the air velocity at a certain point on the wing
Sedaia [141]

Answer:

P1 = 0 gage

P2 = 87.9 lb/ft³

Explanation:

Given data

Airplane flying = 200 mph = 293.33 ft/s

altitude height = 5000-ft

air velocity relative to the airplane = 273 mph = 400.4 ft/s

Solution

we know density at height 5000-ft is 2.04 × 10^{-3} slug/ft³

so here P1 + \frac{\rho v1^2}{2}  = P2 + \frac{\rho v2^2}{2}

and here

P1 = 0 gage

because P1 = atmospheric pressure

and so here put here value and we get

P1 + \frac{\rho v1^2}{2}  = P2 + \frac{\rho v2^2}{2}

0 + \frac{2.048 \times 10^{-3} \times 293.33^2}{2}  = P2 + \frac{2.048 \times 10^{-3} \times 400.4^2}{2}  

solve it we get

P2 = 87.9 lb/ft³

5 0
3 years ago
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