Given: Work W = 3,500 J; Force f = 250 N; Weight w = 765 N
Required: Distance d = ?
Formula: Work = force x distance or W = f x d
Distance d = W/f
d = 3,500 J/250 N
d = 14 m
Answer:
a) The ball goes one-third times higher on X
b) The ball goes three times higher on X.
Explanation:
a)
- As the initial velocity is the same than on Earth, but the free-fall acceleration is three times larger, this means that the only net force acting on the ball (gravity) will be three times larger, so it is clear that the ball will reach to a lower height, as it will slowed down more quickly.
- Kinematically, as we know that the speed becomes zero when the ball reaches to the maximum height, we can use the following kinematic equation:
since vf = 0, solving for Δh, we have:
if v₀ₓ = v₀E, and gₓ = 3*gE, replacing in (1), we get:
Δhₓ = 1/3 * ΔhE
which confirms our intuitive reasoning.
b)
- Now, if the initial velocity is three times larger than the one on Earth, even the acceleration due to gravity is three times larger, we conclude that the ball will go higher than on Earth.
- We can use the same kinematic equation as in (1) replacing Vox by 3*VoE, as follows:
Replacing the right side of (1) in (2), we get:
Δhx = 3* ΔhE
which confirms our intuitive reasoning also.
B
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Answer:
a = - 1.47 [m/s²], descending or going down
Explanation:
To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F = m*a
where:
∑F = Forces applied [N]
m = mass = 10 [kg]
a = acceleration [m/s²]
Let's assume the direction of the upward forces as positive, just as if the movement of the box is upward the acceleration will be positive.
By performing a summation of forces on the vertical axis we obtain all the required forces and other magnitudes to be determined.
where:
g = gravity acceleration = 9.81 [m/s²]
N = normal force measured by the scale = 83.4 [N]
Now replacing:
The acceleration has a negative sign, this means that the elevator is descending at that very moment.
Since the man and the walkway has velocity (which is a vector) moving in the same direction, who would add the velocities together.
That means the relative velocity would be 2 m/s to the East
If you picture it in your mind, imagine walking down an escalator, you feel like you're moving faster than you really are.
In a different example, if the man was moving 0.9 m/s to the West, they are moving in opposite directions, which means you would subtract the 2 velocities.