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3 years ago

HELP!!!!! PLEASE!!!!!!! DUE IN LESS THEN 20 MIN!!!!!!!!!!!! BRAINLIEST!!

Mathematics

1 answer:

SOVA2 [1]3 years ago

3 0

Answer:

— If there are 16 seats in the first row, 18 seats in the second row, 20 seats in the third row , and so on, how many seats are there in all? Follow • 1 ... This is an arithmetic series with a difference of 2. a1 = 16 ... what is an equation equal of a line parallel to y=2/3x-4 and goes through the point (6,7). Answers · 3 ...

Step-by-step explanation:

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A baseball team played 32 games and lost 8. Katy was a catcher in 5/8 of the winning game and 1/4 of the losing games. In how ma

lana66690 [7]

32 - 8 = 24. This means that there were 24 winning games and 8 losing games.

24 multiplied by 5/8 = 15. Katy was a catcher in 15 of the winning games.

8 multiplied by 1/4 = 2. Katy was a catcher in 2 of the losing games.

In total, Katy was a catcher in 17 of the games.

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3 years ago

Read 2 more answers

Line that is parallel to y= -3/2x-1

VLD [36.1K]

Answer:

See below.

Step-by-step explanation:

There is an infinite number of lines parallel to y = -3/2x - 1.

They have the same slope, -3/2, and a different y-intercept.

Examples:

y = -3/2x + 1

y = -3/2x

y = -3/2x - 5

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3 years ago

Robert can paint a certain wall in 4 minutes, while it takes Jack 12 minutes to paint the same wall. How long will it take Rober

olga_2 [115]

It will take 24 minutes.
this is because the lowest common multiple is 24.

hope this helps you

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3 years ago

What is a trick for multiplying 9`s

Dovator [93]

A trick that is good for multiplying 9's is, remember that each time the tens digit changes the number in the ones spaces minuses 1. If you don't understand what I am saying look at the following:-

9
18
27
36
45
54
63
72
81

See the pattern? In the tens place you need to add 1 and in the tens place you need to subtract by 1.

Hope I helped ya!! xD

5 0

3 years ago

Read 2 more answers

Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive

LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let X = number of vehicles that pass the inspection.

The probability of the random variable X is P (X) = 0.70.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

$=(0.70)^{3}\\=0.343$

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

$=1-0.343\\=0.657$

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

= P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

+ P (Only 3rd vehicle passes)

$=(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189$

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

+ P (0 vehicles passes)

$=0.189+(0.30\times0.30\times0.30)\\=0.216$

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let X = all 3 vehicle passes and Y = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

$P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525$

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0

3 years ago